anonymous
  • anonymous
You order 1.5 pounds of turkey at a deli. You will accept the turkey if its weight is between 1.54 lb and 1.46 lb. What absolute value inequality describes the tolerance of the weight of the turkey? Please help I am a bit confused, thank you
Mathematics
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SOLVED
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katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
draw a number line and plot 1.5 on it |dw:1441251633221:dw| preferably in the center
jim_thompson5910
  • jim_thompson5910
then add on 1.54 and 1.46 |dw:1441251655628:dw|
jim_thompson5910
  • jim_thompson5910
how far is 1.54 from 1.5 ?

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More answers

anonymous
  • anonymous
.04
jim_thompson5910
  • jim_thompson5910
|dw:1441251739315:dw|
jim_thompson5910
  • jim_thompson5910
how about from 1.46 to 1.5 ?
anonymous
  • anonymous
Would it be |x-1.5|>=0.04
jim_thompson5910
  • jim_thompson5910
very close
anonymous
  • anonymous
Wait |x-1.5|=<0.04???
jim_thompson5910
  • jim_thompson5910
the general form is |x - T| <= E T = target value E = error you want the absolute value of the difference, |x-T|, to be as small as possible. Ideally 0 The worst you're able to live with is E = 0.04 so yeah it should be |x-1.5| <= 0.04
anonymous
  • anonymous
Thank you saved my life :)
jim_thompson5910
  • jim_thompson5910
you're welcome

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