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anonymous

  • one year ago

You order 1.5 pounds of turkey at a deli. You will accept the turkey if its weight is between 1.54 lb and 1.46 lb. What absolute value inequality describes the tolerance of the weight of the turkey? Please help I am a bit confused, thank you

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  1. jim_thompson5910
    • one year ago
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    draw a number line and plot 1.5 on it |dw:1441251633221:dw| preferably in the center

  2. jim_thompson5910
    • one year ago
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    then add on 1.54 and 1.46 |dw:1441251655628:dw|

  3. jim_thompson5910
    • one year ago
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    how far is 1.54 from 1.5 ?

  4. anonymous
    • one year ago
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    .04

  5. jim_thompson5910
    • one year ago
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    |dw:1441251739315:dw|

  6. jim_thompson5910
    • one year ago
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    how about from 1.46 to 1.5 ?

  7. anonymous
    • one year ago
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    Would it be |x-1.5|>=0.04

  8. jim_thompson5910
    • one year ago
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    very close

  9. anonymous
    • one year ago
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    Wait |x-1.5|=<0.04???

  10. jim_thompson5910
    • one year ago
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    the general form is |x - T| <= E T = target value E = error you want the absolute value of the difference, |x-T|, to be as small as possible. Ideally 0 The worst you're able to live with is E = 0.04 so yeah it should be |x-1.5| <= 0.04

  11. anonymous
    • one year ago
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    Thank you saved my life :)

  12. jim_thompson5910
    • one year ago
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    you're welcome

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