A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Need help real quick,
Its Quadratic Formula,
I solved the question, but i wanna make sure my answer is right.
The question is :
anonymous
 one year ago
Need help real quick, Its Quadratic Formula, I solved the question, but i wanna make sure my answer is right. The question is :

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer I got was dw:1441264767920:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you! :) the answer on the worksheet says its dw:1441265454395:dw so could the worksheet be wrong?

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Ooops :( Let's try again..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okayy, i understand it, but i just dont know how it got that when i have a different answer lol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so maybe i have to + and  it? idk

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Try using your calculator and sub the numbers back in.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[3x^22x=9\]\[x^2\frac{2}{3}x=3\] \[c=\left(\frac{\dfrac{2}{3}}{2}\right)=\left(\frac{1}{3}\right)^2=\frac{1}{9}\] \[x^2\frac{2}{3}x\color{red}{+\frac{1}{9}} = 3 \color{red}{+\frac{1}{9}}\]\[\left(x\frac{1}{3}\right)^2= \frac{28}{9}\]\[x\frac{1}{3} = \pm \frac{\sqrt{28}}{3}\]\[\boxed{x=\pm \frac{\sqrt{28}}{3}+\frac{1}{3}}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0You can check your answer by completing the square, if you're familiar with that method.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0And the answer can be simplified even further from what I have written btw.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is the method we are supposed to use : \[x=b \pm \sqrt{b^24ac}/2a\] over 2a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be the same

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0The first part of that formula is already divided by 2a

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0so what you typed would imply that you need to divide it by 2a again

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Okay so put your formula in quadratic form, \(ax^2+bx+c=0 \longrightarrow 3x^22x9=0\) identify your a, b and c and plug them in to the quadratic.

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441265969581:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0yay our answers match @skullpatrol :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks! i see what i did wrong

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1thanks for asking :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.