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anonymous
 one year ago
Need help real quick,
Its Quadratic Formula,
I solved the question, but i wanna make sure my answer is right.
The question is :
anonymous
 one year ago
Need help real quick, Its Quadratic Formula, I solved the question, but i wanna make sure my answer is right. The question is :

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer I got was dw:1441264767920:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you! :) the answer on the worksheet says its dw:1441265454395:dw so could the worksheet be wrong?

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Ooops :( Let's try again..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okayy, i understand it, but i just dont know how it got that when i have a different answer lol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so maybe i have to + and  it? idk

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Try using your calculator and sub the numbers back in.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3x^22x=9\]\[x^2\frac{2}{3}x=3\] \[c=\left(\frac{\dfrac{2}{3}}{2}\right)=\left(\frac{1}{3}\right)^2=\frac{1}{9}\] \[x^2\frac{2}{3}x\color{red}{+\frac{1}{9}} = 3 \color{red}{+\frac{1}{9}}\]\[\left(x\frac{1}{3}\right)^2= \frac{28}{9}\]\[x\frac{1}{3} = \pm \frac{\sqrt{28}}{3}\]\[\boxed{x=\pm \frac{\sqrt{28}}{3}+\frac{1}{3}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can check your answer by completing the square, if you're familiar with that method.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And the answer can be simplified even further from what I have written btw.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is the method we are supposed to use : \[x=b \pm \sqrt{b^24ac}/2a\] over 2a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be the same

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0The first part of that formula is already divided by 2a

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0so what you typed would imply that you need to divide it by 2a again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so put your formula in quadratic form, \(ax^2+bx+c=0 \longrightarrow 3x^22x9=0\) identify your a, b and c and plug them in to the quadratic.

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441265969581:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay our answers match @skullpatrol :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks! i see what i did wrong

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1thanks for asking :)
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