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anonymous

  • one year ago

Need help real quick, Its Quadratic Formula, I solved the question, but i wanna make sure my answer is right. The question is :

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  1. anonymous
    • one year ago
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    The answer I got was |dw:1441264767920:dw|

  2. anonymous
    • one year ago
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    thank you! :) the answer on the worksheet says its |dw:1441265454395:dw| so could the worksheet be wrong?

  3. skullpatrol
    • one year ago
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    Ooops :( Let's try again..

  4. anonymous
    • one year ago
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    okayy, i understand it, but i just dont know how it got that when i have a different answer lol.

  5. anonymous
    • one year ago
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    so maybe i have to + and - it? idk

  6. skullpatrol
    • one year ago
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    Try using your calculator and sub the numbers back in.

  7. Jhannybean
    • one year ago
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    \[3x^2-2x=9\]\[x^2-\frac{2}{3}x=3\] \[c=\left(\frac{-\dfrac{2}{3}}{2}\right)=\left(-\frac{1}{3}\right)^2=\frac{1}{9}\] \[x^2-\frac{2}{3}x\color{red}{+\frac{1}{9}} = 3 \color{red}{+\frac{1}{9}}\]\[\left(x-\frac{1}{3}\right)^2= \frac{28}{9}\]\[x-\frac{1}{3} = \pm \frac{\sqrt{28}}{3}\]\[\boxed{x=\pm \frac{\sqrt{28}}{3}+\frac{1}{3}}\]

  8. Jhannybean
    • one year ago
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    You can check your answer by completing the square, if you're familiar with that method.

  9. Jhannybean
    • one year ago
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    And the answer can be simplified even further from what I have written btw.

  10. anonymous
    • one year ago
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    This is the method we are supposed to use : \[x=-b \pm \sqrt{b^2-4ac}/2a\] over 2a

  11. anonymous
    • one year ago
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    would it be the same

  12. wolf1728
    • one year ago
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    The first part of that formula is already divided by 2a

  13. anonymous
    • one year ago
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    yeah

  14. wolf1728
    • one year ago
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    so what you typed would imply that you need to divide it by 2a again

  15. Jhannybean
    • one year ago
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    Okay so put your formula in quadratic form, \(ax^2+bx+c=0 \longrightarrow 3x^2-2x-9=0\) identify your a, b and c and plug them in to the quadratic.

  16. anonymous
    • one year ago
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    ohh okay isee

  17. skullpatrol
    • one year ago
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    |dw:1441265969581:dw|

  18. Jhannybean
    • one year ago
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    yay our answers match @skullpatrol :)

  19. anonymous
    • one year ago
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    thanks! i see what i did wrong

  20. skullpatrol
    • one year ago
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    thanks for asking :-)

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spraguer (Moderator)
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