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- anonymous

Need help real quick,
Its Quadratic Formula,
I solved the question, but i wanna make sure my answer is right.
The question is :

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- anonymous

- chestercat

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- anonymous

The answer I got was |dw:1441264767920:dw|

- anonymous

thank you! :)
the answer on the worksheet says its |dw:1441265454395:dw|
so could the worksheet be wrong?

- skullpatrol

Ooops :(
Let's try again..

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- anonymous

okayy, i understand it, but i just dont know how it got that when i have a different answer lol.

- anonymous

so maybe i have to + and - it? idk

- skullpatrol

Try using your calculator and sub the numbers back in.

- Jhannybean

\[3x^2-2x=9\]\[x^2-\frac{2}{3}x=3\]
\[c=\left(\frac{-\dfrac{2}{3}}{2}\right)=\left(-\frac{1}{3}\right)^2=\frac{1}{9}\] \[x^2-\frac{2}{3}x\color{red}{+\frac{1}{9}} = 3 \color{red}{+\frac{1}{9}}\]\[\left(x-\frac{1}{3}\right)^2= \frac{28}{9}\]\[x-\frac{1}{3} = \pm \frac{\sqrt{28}}{3}\]\[\boxed{x=\pm \frac{\sqrt{28}}{3}+\frac{1}{3}}\]

- Jhannybean

You can check your answer by completing the square, if you're familiar with that method.

- Jhannybean

And the answer can be simplified even further from what I have written btw.

- anonymous

This is the method we are supposed to use : \[x=-b \pm \sqrt{b^2-4ac}/2a\]
over 2a

- anonymous

would it be the same

- wolf1728

The first part of that formula is already divided by 2a

- anonymous

yeah

- wolf1728

so what you typed would imply that you need to divide it by 2a again

- Jhannybean

Okay so put your formula in quadratic form, \(ax^2+bx+c=0 \longrightarrow 3x^2-2x-9=0\) identify your a, b and c and plug them in to the quadratic.

- anonymous

ohh okay isee

- skullpatrol

|dw:1441265969581:dw|

- Jhannybean

yay our answers match @skullpatrol :)

- anonymous

thanks! i see what i did wrong

- skullpatrol

thanks for asking :-)

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