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anonymous
 one year ago
The pointslope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
(A) x – 4y = 8
(B) x – 4y = 2
(C) 4x – y = 8
(D) 4x – y = 2
anonymous
 one year ago
The pointslope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? (A) x – 4y = 8 (B) x – 4y = 2 (C) 4x – y = 8 (D) 4x – y = 2

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.0slope of the line = ( 1  (3) / 12  (4) = 4/16 = 1/4 plugging in y = 3 , x = 4 and m = 1/4 into the pointslope form: y  (3) = (1/4)(x  (4) y + 3 = (1/4) x + 1 multiply through by 4 4y + 12 = x + 4 can you continue/

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0subtract 4 from both sides 4y + 8 = x subtract 4y from both sides 8 = x  4y which is the same as x  4y = 8 Standard form

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0the last step was just swapping sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i got it thank you?
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