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zarkam21

  • one year ago

Help, will medal

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  1. zarkam21
    • one year ago
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  2. welshfella
    • one year ago
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    add up the last values in each row what do you get/

  3. welshfella
    • one year ago
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    That large E like character means the ' sum of all these 10 values'

  4. welshfella
    • one year ago
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    this sum is the answer to step 2

  5. anonymous
    • one year ago
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    Is this Sigma notation? mind if i stick around?

  6. zarkam21
    • one year ago
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    Well for the first row the total is 0. And for the second row is 224

  7. zarkam21
    • one year ago
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    @welshfella

  8. zarkam21
    • one year ago
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    @welshfella,, are you there?

  9. anonymous
    • one year ago
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    @cc_peach

  10. zarkam21
    • one year ago
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    Idk where he went, I really need help

  11. anonymous
    • one year ago
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    the second row is 224, that's answer for step 2

  12. anonymous
    • one year ago
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    \[Standard deviation(S)=\sqrt{\frac{ \sum_{i=1}^{10} (x _{i}-\mu)^2}{ n-1 }}\]=\[\sqrt{\frac{ 224 }{ 10-1 }}\]

  13. zarkam21
    • one year ago
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    So for step 3, it is 224 divided by 9?

  14. welshfella
    • one year ago
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    = sqrt((24.89)

  15. welshfella
    • one year ago
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    - sorry i got called away

  16. anonymous
    • one year ago
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    no, it's \[\sqrt{\frac{ 224 }{ 9 }}\]

  17. zarkam21
    • one year ago
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    So 24.89

  18. welshfella
    • one year ago
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    divide 224 by 9 first . Then take the square root

  19. zarkam21
    • one year ago
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    For step 3 ,,, 24.89

  20. welshfella
    • one year ago
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    the standard deviation = sqrt (24.89)

  21. zarkam21
    • one year ago
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    Okay so for step three the answer is sqrt 24.89

  22. welshfella
    • one year ago
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    yes

  23. welshfella
    • one year ago
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    so grab your calculator and evaluate it

  24. zarkam21
    • one year ago
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    4.99

  25. welshfella
    • one year ago
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    yea

  26. zarkam21
    • one year ago
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    Is that all?

  27. zarkam21
    • one year ago
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    Thank you

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