zarkam21
  • zarkam21
Help, will medal
Mathematics
schrodinger
  • schrodinger
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zarkam21
  • zarkam21
1 Attachment
welshfella
  • welshfella
add up the last values in each row what do you get/
welshfella
  • welshfella
That large E like character means the ' sum of all these 10 values'

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welshfella
  • welshfella
this sum is the answer to step 2
anonymous
  • anonymous
Is this Sigma notation? mind if i stick around?
zarkam21
  • zarkam21
Well for the first row the total is 0. And for the second row is 224
zarkam21
  • zarkam21
zarkam21
  • zarkam21
@welshfella,, are you there?
anonymous
  • anonymous
zarkam21
  • zarkam21
Idk where he went, I really need help
anonymous
  • anonymous
the second row is 224, that's answer for step 2
anonymous
  • anonymous
\[Standard deviation(S)=\sqrt{\frac{ \sum_{i=1}^{10} (x _{i}-\mu)^2}{ n-1 }}\]=\[\sqrt{\frac{ 224 }{ 10-1 }}\]
zarkam21
  • zarkam21
So for step 3, it is 224 divided by 9?
welshfella
  • welshfella
= sqrt((24.89)
welshfella
  • welshfella
- sorry i got called away
anonymous
  • anonymous
no, it's \[\sqrt{\frac{ 224 }{ 9 }}\]
zarkam21
  • zarkam21
So 24.89
welshfella
  • welshfella
divide 224 by 9 first . Then take the square root
zarkam21
  • zarkam21
For step 3 ,,, 24.89
welshfella
  • welshfella
the standard deviation = sqrt (24.89)
zarkam21
  • zarkam21
Okay so for step three the answer is sqrt 24.89
welshfella
  • welshfella
yes
welshfella
  • welshfella
so grab your calculator and evaluate it
zarkam21
  • zarkam21
4.99
welshfella
  • welshfella
yea
zarkam21
  • zarkam21
Is that all?
zarkam21
  • zarkam21
Thank you

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