A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.
x = 0, solution is not extraneous
x = 0, solution is extraneous
x = 12, solution is not extraneous
x = 12, solution is extraneous
anonymous
 one year ago
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution. x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x=12, solution is extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you wanted an explanation, go about this like a normal algebraic explanation (aka try to find the value of x and don't worry about the extraneous part yet).\[4\sqrt{x3} = 12\]\[\sqrt{x3}=3~~~\text{<Take note of this, we'll come back here later.}\]\[x  3=9\]\[x=12\]Ok, great. We got a solution. Now, the term extraneous solution means that the solution that we found doesn't actually work. Let's test the solution by plugging it back in.\[4\sqrt{x3} = 12\]\[4\sqrt{123}=12\]\[4\sqrt{9}=12\]\[12\ne12\]Since 12 doesn't equal 12, the solution doesn't work. Now, if you go back to that second step, You might've noticed that \(\sqrt{x3}\) can NEVER BE NEGATIVE, yet it is set equal to a negative number. (when a \(\sqrt{}\) is given to you, it is assumed positive. So, \(\sqrt{x^2} = x\), not x because it can never be negative. However, if you take the squareroot to solve an equation, like \(x^2=9\), then you get \(x=\pm3\) because you're trying to find all possible solutions.) This is something that would immediately tip you off that the solution you WILL get is extraneous, because this is impossible to satisfy.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.