Suppose a rock is thrown upwards from the top of a building 200 feet high with an initial velocity of 96 feet per second. The height (in feet) of the rock above the ground t seconds after being released is given by the formula
h(t) = -16t^2 + 96t + 200
1.When will it hit the ground?
2.How high will it be after 2.1 seconds?
3.What is the maximum height?

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1. It will hit the ground when h(t) = 0 so you need to solve
\[-16t^2+96t+200=0\]

try the quadratic formula

Would it be t=3-√ 43/2=-1.63 and 3+√ 43/2=7.63

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