Help!!! Scientific Notation. Document below

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Help!!! Scientific Notation. Document below

Mathematics
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I need help with A B C and D

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question #1 we need to compute the distance Venus-Earth
ok
108,000,000 and 150,000,000
from your table, we can write this: \[\Large d = 150 \cdot {10^6} - 108 \cdot {10^6} = \left( {150 - 108} \right) \cdot {10^6} = ...?\]
32 x 1,000,000
so then 32,000,000 is the difference/what they have to travel from venus to earth?
  • phi
42, not 32
better is: \[\Large \begin{gathered} d = 150 \cdot {10^6} - 108 \cdot {10^6} = \left( {150 - 108} \right) \cdot {10^6} = \hfill \\ = 42 \cdot {10^6} = 4.2 \cdot {10^7} \hfill \\ \end{gathered} \]
oh ok
so then I have to keep on going until jupiter and then add all of them together right?
question B we have to compute the sum of the distance of Mercury, Venus and Earth, first. Such sum is: \[\large d = 57 \cdot {10^6} + 108 \cdot {10^6} + 150 \cdot {10^6} = \left( {57 + 108 + 150} \right) \cdot {10^6} = ...?\]
\[d = 57 \cdot {10^6} + 108 \cdot {10^6} + 150 \cdot {10^6} = \left( {57 + 108 + 150} \right) \cdot {10^6} = ...?\]
315 x 10^6?
correct! second we have to compare that distance with the distance of Neptune, which is: \[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6}\]
? whats d^1??
d1 is the distance of Neptune from the Sun Is the distance of Neptune from the Sun greater or less than the sum of distances above?
greater?
correct since: \[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6} > 42 \cdot {10^6}\]
ohh
can you type that in the document please and then send it to me through here??
for b? please
oops.. since : \[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6} > 315 \cdot {10^6}\] sorry for my typo
its all right :D
now, let's go to question C)
lol ok
if I multiply the distance of the Earth from the Sun, by 10, I get this new distance: \[\Large L = 150 \cdot {10^6} \cdot 10 = 150 \cdot {10^7}\]
ok
and that distance is very close to the distance of Saturn which is: \[\Large {L_1} = 1.43 \cdot {10^9} = 143 \cdot {10^7}\] am I right?
i think so
so what is the right name of planet?
saturn
right?
correct!
now, let's go on question D)
haha ok
first, we have to compute the distance Saturn-Earth, which is: \[\Large D = 1430 \cdot {10^6} - 150 \cdot {10^6} = ...?\]
1280 x 10^6?
correct! now the requested time is: time=distance over speed and the speed of Shuttle is: \[\Large v = 28000 = 28 \cdot {10^3}{\text{Km/h}}\] so the requested time is: \[\Large t = \frac{{{\text{distance}}}}{{{\text{speed}}}} = \frac{{1280 \cdot {{10}^6}}}{{28 \cdot {{10}^3}}} = \frac{{1280}}{{28}}{10^{6 - 3}} = ...hours\]
45.71 x 10^3?
that's right!
so thats it?
yes!
thanks!! i just have a question... could you help solve the rest of part a??
yes! sure!
ok i just have trouble calculating the distances in scientific notation.. showing my work
we need to know the distance Venus-Jupiter, which is: \[\Large d = 779 \cdot {10^6} - 108 \cdot {10^6} = \left( {779 - 108} \right) \cdot {10^6} = ...?\]
yea we already did the one from venus to earth so now i guess we have to calculate from earth to mars
sorry are you asking for question A) right?
yes
ok! then we have to compute the distance Venus-Jupiter
yea
and such distance is: \[\Large d = 779 \cdot {10^6} - 108 \cdot {10^6} = \left( {779 - 108} \right) \cdot {10^6} = ...?\]
671 x 10^6?
yes! correct! :)
is that all?
yes! we have finished!
wow! yay thanks!! :D
:) :)

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