I. Given the following polynomial:
II.
Use the quadratic formula to solve the following:

- anonymous

I. Given the following polynomial:
II.
Use the quadratic formula to solve the following:

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- anonymous

help me i dont kno mathat all

##### 1 Attachment

- Nnesha

what's the equation ?

- Nnesha

post ur question here :=)

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## More answers

- Nnesha

`Given the following polynomial:` ???

- anonymous

look at the attachment

- Nnesha

i didn't find the equation can you please post it here ?

- anonymous

how do i do that?

- Nnesha

like type in the equation toool ?

- Nnesha

take a screenshot ?

- anonymous

The value of the discriminant is 169.
There are 2 real roots.
There are 2 irrational roots.
The graph intersects the y-axis twice.
The parabola is directed upward.
The axis of symmetry is located at
The vertex is located at:
The roots are:
The graph intersects the y axis at (0, -15).
The graph intersects the x-axis at (-5, 0) and (1.5, 0)
II.
Use the quadratic formula to solve the following:

- Nnesha

what's the polynomial ?

- Nnesha

there should be an equation Ax^2+Bx+C like this

- anonymous

2xexponet2+7x-15=0

- Nnesha

\[\huge\rm 2x^2+7x-15=0\]
quadratic equation ax^2+bx+c quadratic equation
where a=leading coefficient
b=middle term
c-constant term
so what is a
b and c in that equation ?
\[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]quadratic formula

- Nnesha

\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant`
you can use this to find if the equation is factorable or not
if ` b^2-4ac > 0` then there are 2 real zeros
if ` b^2-4ac = 0` then there is one real root
if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)

- Nnesha

substitute a b and c value into b^2 -4ac
do you get 169 ?

- anonymous

idk how to domath miss

- Nnesha

Ax^2+Bx+C
standard form equation of parabola
where a = leading coefficient
b= middle term
c=constant term
now look at this equation 2x^2+7x-15
what is a b and c ?

- anonymous

2x is a 7x is b

- Nnesha

just the coefficient
2 =a
7=b
c = ?

- anonymous

15

- Nnesha

-15

- Nnesha

alright \[\huge\rm b^2-4ac\] substitute b a and c values then sovle

- Nnesha

solve*

- anonymous

how

- Nnesha

just replace b with 7
a with 2
c with -15

- Nnesha

here is how i would replace b with 7...... \[\rm (7)^2-4ac\] ur turn replace a with 2 and c with -15

- anonymous

49-8-15 that what i got

- Nnesha

it's 4 times a times c
it would bbe \[49 -8(-15)\]
now solve

- Nnesha

hello ?

- anonymous

idk

- Nnesha

that's not an answer
you don't know or you don't want to do it ?
you can use calculator
just put 49-8(-15) into the calculator that's it

- anonymous

56

- Nnesha

that's not correct!

- Nnesha

49 -8(-15)
first multiply -8 times -15
then add 49

- anonymous

thats what i got both times

- Nnesha

-8 times -15 = ?

- anonymous

1065

- Nnesha

did you really get that ?

- anonymous

yea

- Nnesha

guess what ... try again
make sure you typed -8 times -15 into the calculator

- anonymous

120

- Nnesha

yes right 49+120 = ?
that would be discriminant

- anonymous

169

- Nnesha

yes right so first
sentence is right ?
` The value of the discriminant is 169`

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