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theta = 44°
and I need the distance between the two people

What formula would I use to find the time that takes the ball to fly from one person to another?

Disregard the previous long 3 part reply, that is more for myself.

yeah, you don't need to know how high it went, just how long it was in the air for

Which formula am I starting to use, can you please tell me?

ok, so we need `22sin(44) / 9.81` seconds, (roughly 4.5 × 2 = 9) seconds.

ok, and then how would I use the time between them to find the distance between them>

Makes sense, right?

oh, so d=11cos(44)×(11sin(44)÷9.81)= (11/19.62) sin(88)

11cos(44) is v
11sin(44) / 9.81 is time

actually time is 22sin(44)/9.81
remember we need time it takes for ball to go from Julie to Sarah.

or rather full time is 2t.

so t is 2t:)(()()()()

Yeah

Oh Vy=Voy - gt is what we would have used. Tnx

No problem