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anonymous

  • one year ago

A.Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process. B.Megan solved a similar equation below. Is Megan's solution correct? Explain why or why not. 3(2x − 4) = 5x − 1 6x − 12 = 5x − 1 11x − 12 = –1 11x = 11 x = 11

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  1. anonymous
    • one year ago
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    ok please distribute the -2 to the parentheses on the right side

  2. anonymous
    • one year ago
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    (3x+-2)

  3. calculusxy
    • one year ago
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    \[\large 5x - 4 =-2(3x + 2) => 5x - 4 = -2(3x) + -2(2)\]

  4. calculusxy
    • one year ago
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    What is -2(3x) and -2(2) ?

  5. anonymous
    • one year ago
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    ^^ would that be the top piece for my answer cuz i have to put the steps on how i got the answer

  6. calculusxy
    • one year ago
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    Yes

  7. anonymous
    • one year ago
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    ok

  8. anonymous
    • one year ago
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    just finish going through how to get it and you will know what to put for your answer but don't worry about it yet

  9. anonymous
    • one year ago
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    then what

  10. anonymous
    • one year ago
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    ok

  11. anonymous
    • one year ago
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    what next

  12. calculusxy
    • one year ago
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    What did you get after your distributed -2 to the numbers inside of the parenthesis?

  13. anonymous
    • one year ago
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    -2(3x)=-6 -2(2)= -4

  14. calculusxy
    • one year ago
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    Since you multiplied -2 with 3x, it's -6x. \[\large 5x - 4 = -6x -4 => 5x - 4 + 6x = -6x - 4 + 6x => 11x -4 = -4\]

  15. calculusxy
    • one year ago
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    \[11x -4 = -4\]

  16. anonymous
    • one year ago
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    thats it?

  17. anonymous
    • one year ago
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  18. calculusxy
    • one year ago
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    And then solve for x.

  19. anonymous
    • one year ago
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    like that

  20. anonymous
    • one year ago
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    so far

  21. anonymous
    • one year ago
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    its worth 10 points i really need to pass this question lol

  22. anonymous
    • one year ago
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    anyone??

  23. calculusxy
    • one year ago
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    Instead of putting this symbol \[=>\] just press 'enter' and go to the line below. also you need to solve for x. \[\large 11x - 4 = -4 \] \[\large 11x - 4 + 4 = -4 + 4\] \[\large 11x = 0\] this shows that x is 0

  24. anonymous
    • one year ago
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    so that

  25. anonymous
    • one year ago
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    what about part B

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