I am VERY confused to even know how to begin to solve this problem. I need someone to walk me through this problem. Medal as always. Two students in your class, Wilson and Alexis, are disputing a function. Wilson says that for the function, between x = -1 and x = 1, the average rate of change is 0. Alexis says that for the function, between x = -1 and x = 1, the graph goes up through a turning point, and then back down. Explain how Wilson and Alexis can both be correct, using complete sentences.

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I am VERY confused to even know how to begin to solve this problem. I need someone to walk me through this problem. Medal as always. Two students in your class, Wilson and Alexis, are disputing a function. Wilson says that for the function, between x = -1 and x = 1, the average rate of change is 0. Alexis says that for the function, between x = -1 and x = 1, the graph goes up through a turning point, and then back down. Explain how Wilson and Alexis can both be correct, using complete sentences.

Mathematics
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@ganeshie8 @Hero @Nnesha @iambatman much appreciation.
both can be wrong eh hun or nah ?
Well I'm not sure, it just says explain how both of them ~could~ be correct. For this should I use my knowledge of graphing functions and translation meanings or something different?

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ohh nvm i thought both x are positive hm
well if slope is zero you will draw horizontal line
do you have graph with this question or table ?
No there is no graph or table.
i will use slope formula (average rate of change - slope )\[\huge\rm \frac{ y_2 - y_1}{ x_2 -x_1 }\] if slope is 0 then you should get 0 at the numerator substitute x's values x=1 and x=-1
What about Alexis?
Alexis says that for the function, between x = -1 and x = 1, the graph goes up through a turning point, and then back down. goes up through a turning point, then back down? ?
well how would you get 0 at the numerator in order to get zero both y values should be the same like y_1 = 2 y_2 = 2 then you will get 0 \[\frac{ 2-2 }{ 1-(-1) } = \frac{ 0 }{ 2}\] when slope is zero you will draw horizontal line |dw:1441304852375:dw| x values are increasing but y's is constant
so i guess he meant x values are going up y values are the same
make sense ? :D
Yes, thank you very much for your time!! xx
np :=)

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