## anonymous one year ago factor 2x^2+3x+11

1. anonymous

Its not rational, so pretty much put prime

2. anonymous

You're going to want t complete the square with this one

3. anonymous

@Kimes are you there?

4. anonymous

yeah sorry, but i got x(2x+3)+11

5. anonymous

Cannot be factored. A plot is attached.

6. anonymous

The only thing you can do is use the completing the square method to put in a form to solve for x.

7. anonymous

Ah okay I got it, thanks

8. anonymous

Begin with grouping terms with x in them. $(2x^2+3x)+11$$2\left(x^2+\frac{3}{2}x\right)+11$$2\left(x^2+\frac{3}{2}x+\frac{9}{16}\right)+11 - \frac{9}{8}$$\boxed{2\left(x+\frac{3}{4}\right)^2+\frac{79}{8}}$