## anonymous one year ago Need Help!! Please!! Medal!!

1. anonymous

The Graduate Record Examinations are widely used to help predict the performance of applicants to graduate schools. The range of possible scores on a GRE is 200 to 900. The psychology department at a university finds that the scores of its applicants on the quantitative GRE are approximately normal with mean = 544 and standard deviation = 103. Use your calculator or computer to find the relative frequency of applicants whose score X satisfies the following conditions: (As part of your answer, draw a standard normal curve and shade the area under the curve that represented the answer to the question; do this on scratch paper and provide a one-sentence description for the assignment). X < 500

2. anonymous

Please tag anyone you know that is good at math!!

3. anonymous

That is not the same question as mine. Can you just tag some people that are good at math please. @tiff9702

4. anonymous

@ganeshie8 @dan815 @Michele_Laino @iambatman @pooja195 @Hero

5. Michele_Laino

here is the situation described by your exercise: |dw:1441305133103:dw|

6. anonymous

Okay. So how would I properly describe it though? @Michele_Laino

7. Michele_Laino

now we have to compute the subsequent quantity: $\Large t = \frac{{544 - 500}}{{103}} = ...?$

8. Michele_Laino

yes! I think that you have to describe the steps in order to get my drawing above

9. anonymous

So the 1st step is to compute the subsequent quantity?

10. anonymous

I got 0.427

11. Michele_Laino

ok! we can round off that result to 0.43

12. Michele_Laino

now we have to use the table of the "erf" function, and we get that the relative frequency is: $\Large r = 50 - 16.28 = ...\%$

13. anonymous

So would I write that the 1st step is to compute the subsequent quantity?

14. anonymous

Okay I got 33.72.

15. Michele_Laino

yes! the first step is to compute the distance 0f 500 from the mean 544 in units of the standard deviation and yes! that percentage is the requested relative frequency

16. anonymous

Okay I got it so far :D

17. Michele_Laino

:)

18. anonymous

Is that all to get the graph? @Michele_Laino

19. anonymous

Wow! You make everything seem so easy! Thank you so much!!! @Michele_Laino

20. Michele_Laino

yes! my graph is all what we can do :)

21. Michele_Laino

:)

22. anonymous

Thank You!

23. Michele_Laino

thanks! :) :)