A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Help would be appreciated! Will Medal! State the minimum and maximum values (if any) of the linear expression under the given constraints: 1. 0<=y<=6-x 0<=x<=4 x+3y

  • This Question is Open
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @robtobey

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Any ideas?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If it helps this is Algebra.

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    An analysis of the inequalities by the Mathematica program is attached.

    1 Attachment
  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I still dont understand what to do with that information

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It just rewrites the question

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't understand what the third line is saying

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where did the 4+3*2=10 come from and what does that mean?

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Would x=4 and y=2 be the maximum while x=0 and y=6 be the minimum or vice versa? And when the equation is graphed does it curve?

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please I still need help.

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why have you been typing for so long but nothing pops up.

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x + 3y ( 0<=y<=2 && 0<=x<=4) || (2<y<6 && 0<=x<=6-y) || (y==6 && x==0 ) When y is 6 then x has to be 0 from (y==6 && x==0 ) . Then x+3y is 0 + 3*6 = 18, a maximum value. From ( 0 <= y <= 2 && 0 <= x <= 4 ) , x and y can be zero at the same time making x + 3y = 0, a minimum.

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That is about all I can do with this problem.

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So how do you graph it though

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    And thanks for your help so far

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Don't think I can help you on the graphing at this time. Sorry about that.

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks anyway

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Have good day.

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Bye

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.