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Destinyyyy

  • one year ago

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  1. Destinyyyy
    • one year ago
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    Find the real solutions of the equation. 4x^2/3 -11x^1/3 -3=0

  2. Destinyyyy
    • one year ago
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    @Nnesha @IrishBoy123

  3. campbell_st
    • one year ago
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    ok.. so this is an equation that can be written as a quadratic use a substitution \[u = x^{\frac{1}{3}}\] so the equation is \[4u^2 - 11u - 3 = 0\] this can be factored to (4u + 1)(u - 3) = 0 so then solve for u... does that make sense so far...?

  4. Destinyyyy
    • one year ago
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    So I can do substitution? Okay

  5. campbell_st
    • one year ago
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    yes... that is the easiest method to solve this equation when you get the solutions for u, then let the solutions equal \[x^{\frac{1}{3}}\]

  6. campbell_st
    • one year ago
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    then you can solve for x

  7. Destinyyyy
    • one year ago
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    Yes I know that.. I assumed I couldn't solve that way since it didnt say I could

  8. Destinyyyy
    • one year ago
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    u= -1/4 and u= 3

  9. campbell_st
    • one year ago
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    well it will give the real solutions... I'd always treat questions of this type as quadratics.... so you need to solve \[x^{\frac{1}{3}} = -\frac{1}{4},~~and~~~~, x^{\frac{1}{3}} = 1\]

  10. Destinyyyy
    • one year ago
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    So x= 32 and 27 correct?

  11. Destinyyyy
    • one year ago
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    Oops. -1/64, 27

  12. campbell_st
    • one year ago
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    yes that's a lot better

  13. Destinyyyy
    • one year ago
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    Thank you.

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