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rayman5766

  • one year ago

The vertices of a trapezoid are shown below. P(0, 0), Q(4, 0), R(4, 7), S(0, 14) This trapezoid is dilated about the origin by a scale factor of 3. What is the location of point S'? A. (3, 42) B. (0, 17) C. (3, 17) D. (0, 42)

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  1. rayman5766
    • one year ago
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    I said it could be c but I don't have any graph paper

  2. campbell_st
    • one year ago
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    well the distance from P to S is how far...?

  3. rayman5766
    • one year ago
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    p is 0 and s 14

  4. campbell_st
    • one year ago
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    so what distance is it...?

  5. rayman5766
    • one year ago
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    oh wow I didn't put to much thought in to this now thinking about B

  6. campbell_st
    • one year ago
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    when you find it, the distance is along the y- axis... so using the scaling factor of 3 and multiply the length by 3 then that will be the new location of s on the y-axis

  7. campbell_st
    • one year ago
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    |dw:1441310273404:dw|

  8. rayman5766
    • one year ago
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    d

  9. rayman5766
    • one year ago
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    well yes are noo

  10. campbell_st
    • one year ago
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    well it seems the sensible answer

  11. rayman5766
    • one year ago
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    I am taking that as a no well it can't be c or b because it can't go to 3,17 to 3,42

  12. campbell_st
    • one year ago
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    it is the only sensible answer D

  13. campbell_st
    • one year ago
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    and if you don't have graph paper download geogebra and then you have something you can use for these questions https://www.geogebra.org/

  14. rayman5766
    • one year ago
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    i am sorry i just been on this question for hours nd i cant think and i have 2more to get done with but thanks

  15. rayman5766
    • one year ago
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    also sorry for wasting you time

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