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anonymous

  • one year ago

Rewrite the following equation in exponential form. log 25 = 2 5

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  1. Nnesha
    • one year ago
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    |dw:1441312943928:dw|

  2. anonymous
    • one year ago
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    well the answers are ... 2^5=25 5^2=25 25^2=25

  3. anonymous
    • one year ago
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    so out of those what is the answer?

  4. Nnesha
    • one year ago
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    you tell me which one is it ?

  5. anonymous
    • one year ago
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    I dont know, im bad at this

  6. Nnesha
    • one year ago
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    look at the drawing \[\huge\rm log_5 25 =2\] this question base is 5

  7. anonymous
    • one year ago
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    so it would be 5^2=25 ?

  8. Nnesha
    • one year ago
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    that's right!

  9. anonymous
    • one year ago
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    thank you!

  10. anonymous
    • one year ago
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    can you help me on the rest of them?? please

  11. Nnesha
    • one year ago
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    i'll try not sure :=)

  12. anonymous
    • one year ago
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    ok it says.. rewrite the following statement in logarithmic form. 6^1=6

  13. Nnesha
    • one year ago
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    try it! same like last one but it backwards

  14. anonymous
    • one year ago
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    the answers are |dw:1441313487490:dw| |dw:1441313539295:dw| |dw:1441313569281:dw|

  15. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @tuckerderanleau ok it says.. rewrite the following statement in logarithmic form. 6^1=6 \(\color{blue}{\text{End of Quote}}\) what is base in this question

  16. anonymous
    • one year ago
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    6

  17. Nnesha
    • one year ago
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    yes right |dw:1441313739403:dw| move the exponent to the right side

  18. anonymous
    • one year ago
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    so the answer is |dw:1441313836139:dw|

  19. Nnesha
    • one year ago
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    great!

  20. anonymous
    • one year ago
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    thanks

  21. Nnesha
    • one year ago
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    np just practice !

  22. anonymous
    • one year ago
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    and how do i find the value ?|dw:1441313910815:dw|

  23. anonymous
    • one year ago
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    is the value 0?

  24. Nnesha
    • one year ago
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    change of base formula

  25. Nnesha
    • one year ago
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    \[\huge\rm log_b a= \frac{ lob a}{ \log b }\]

  26. Nnesha
    • one year ago
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    did you apply that ?

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