shaleiah
  • shaleiah
Help, Medal and Fan reward.
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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shaleiah
  • shaleiah
I'm guessing 'B'
shaleiah
  • shaleiah
anonymous
  • anonymous
how you got B ?

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shaleiah
  • shaleiah
I multiplied 5*11 and 17*17.
anonymous
  • anonymous
use \[x ^{a}*x ^{b}=x ^{a+b}\]
shaleiah
  • shaleiah
\[y ^{5/17}+y ^{11/17}\]
shaleiah
  • shaleiah
16/17
shaleiah
  • shaleiah
The radical would be \[\sqrt[16]{y ^{17}}\]
shaleiah
  • shaleiah
Right?
anonymous
  • anonymous
not right look \[y ^{\frac{ 16 }{ 17 }}=(y ^{16})^{\frac{ 1 }{ 17 }}\]
shaleiah
  • shaleiah
@IrishBoy123 Please help. I'm still confused.
shaleiah
  • shaleiah
Would the answer be 'A' since y is equal to 16??
anonymous
  • anonymous
yes right
anonymous
  • anonymous
A is the answer!!
IrishBoy123
  • IrishBoy123
\[\large y^{\frac{5}{17}}.y^{\frac{11}{17}} =y^{\frac{5+11}{17}}=y^{\frac{16}{17}} =\sqrt[17]{y^{16}}\]
IrishBoy123
  • IrishBoy123
NB 1\17 calls for 17th root of something...
IrishBoy123
  • IrishBoy123
and that something is to the 16th power

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