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anonymous
 one year ago
If the circle with center O has area 9 pi, what is the area of equilateral triangle ABC?
anonymous
 one year ago
If the circle with center O has area 9 pi, what is the area of equilateral triangle ABC?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441314908068:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0area is \(9\pi \)r right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea so the diameter is 6

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0ok so you got that the height is 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441315064479:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^is that for the height of the triangle? Like we're converting the 6 to an apropriate side that corresponds to the 306090 triangle right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you are way ahead of me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441315150836:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0yeah each side of your triangle is \[\frac{2\times 6}{\sqrt3}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you lost me there height of the triangle is 6

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441315234092:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0the short leg of either right triangle on the left and right is \(\frac{6}{\sqrt{3}}\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0area of each right triangle is base times height

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0rather one half base times height but together it is base times height so \[6\times \frac{6}{\sqrt3}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441315367905:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait what? so \[4\sqrt{3}\] is for the bottom left and right of the traingles?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441315446382:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0the short leg is the long leg divided by root 3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0so the area of the two right triangles taken together is base times height

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0ok i see \[\frac{6}{\sqrt{3}}=2\sqrt3\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0so total area is \[6\times 2\sqrt3 = 12\sqrt 3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0fml i've been doin it all wrong this whole time

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you got the height right away then i think you confused yourself and turned the height in to something else first you said it was 6 (correct) then you said it was \(4\sqrt3\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So dw:1441315715658:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0yeah that looks good to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont get why it's 2 root 3 is the problem like why does it convert that way and the process

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought in a 306090 triangle the root three would replace the 6

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0k lets go slow you said you had a 30  60 90 triangle right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0the ratios are \[1:\sqrt3:2\] for short leg ; long leg ; hypotenuse

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0the long leg here is 6

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0so the short leg is \[\frac{6}{\sqrt3}=2\sqrt3\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you multiply the short leg by root 3 to get the long leg right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0so to go the other way, from the long leg to the short leg, you divide

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea but like why is it that way? shouldn't the short leg not contain the root 3?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0if the short leg was a whole number the long leg would contain root 3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0but the long leg is a whole number, so the short leg as the root 3 in it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0it is not weird, only seems weird because you usually see it with the short leg a whole number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmmm yea i guess so
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