BloomLocke367
  • BloomLocke367
Okay, I have 2 kinesmatic equations written down to find the change in velocity... I don't know which one is correct or if they both are correct
AP Physics
chestercat
  • chestercat
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BloomLocke367
  • BloomLocke367
@mathmate you seem to know this stuff
BloomLocke367
  • BloomLocke367
I have |dw:1441317362885:dw| are they both correct?
BloomLocke367
  • BloomLocke367
They both are usable, right?

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anonymous
  • anonymous
Average velocity is equal to (initial velocity + final velocity)/2 Velocity is equal to distance/time Since final position-initial position is displacement and displacement is a distance. You are correct.
BloomLocke367
  • BloomLocke367
okay thank you XD I just wanted to make sure I was doing the correct thing. xp thanks!
anonymous
  • anonymous
Ah! Good idea to check your equation.
BloomLocke367
  • BloomLocke367
mhm c:
BloomLocke367
  • BloomLocke367
Can you check my work @Shalante I used the first equation I wrote for this: A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?
mathmate
  • mathmate
Sorry, I was afk! :( 5.00*10^2 m / (1.00*10^2 km/h) = 500 /(100 *1000/3600) m/(m/s) = 5.000*3.600 s = 18.00 s = 18.0 s Not sure how you got 19.8 m. Also, the choice of the two ways to find the average velocity depends on the given information.

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