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BloomLocke367
 one year ago
Okay, I have 2 kinesmatic equations written down to find the change in velocity... I don't know which one is correct or if they both are correct
BloomLocke367
 one year ago
Okay, I have 2 kinesmatic equations written down to find the change in velocity... I don't know which one is correct or if they both are correct

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BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1@mathmate you seem to know this stuff

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I have dw:1441317362885:dw are they both correct?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1They both are usable, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Average velocity is equal to (initial velocity + final velocity)/2 Velocity is equal to distance/time Since final positioninitial position is displacement and displacement is a distance. You are correct.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1okay thank you XD I just wanted to make sure I was doing the correct thing. xp thanks!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah! Good idea to check your equation.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Can you check my work @Shalante I used the first equation I wrote for this: A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I was afk! :( 5.00*10^2 m / (1.00*10^2 km/h) = 500 /(100 *1000/3600) m/(m/s) = 5.000*3.600 s = 18.00 s = 18.0 s Not sure how you got 19.8 m. Also, the choice of the two ways to find the average velocity depends on the given information.
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