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Average velocity is equal to (initial velocity + final velocity)/2
Velocity is equal to distance/time
Since final position-initial position is displacement and displacement is a distance.
You are correct.
okay thank you XD I just wanted to make sure I was doing the correct thing. xp thanks!
Ah! Good idea to check your equation.
Can you check my work @Shalante I used the first equation I wrote for this:
A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?
Sorry, I was afk! :(
5.00*10^2 m / (1.00*10^2 km/h)
= 500 /(100 *1000/3600) m/(m/s)
= 5.000*3.600 s
= 18.00 s
= 18.0 s
Not sure how you got 19.8 m.
Also, the choice of the two ways to find the average velocity depends on the given information.