Okay, I have 2 kinesmatic equations written down to find the change in velocity... I don't know which one is correct or if they both are correct
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
@mathmate you seem to know this stuff
I have |dw:1441317362885:dw| are they both correct?
Not the answer you are looking for? Search for more explanations.
Average velocity is equal to (initial velocity + final velocity)/2
Velocity is equal to distance/time
Since final position-initial position is displacement and displacement is a distance.
You are correct.
okay thank you XD I just wanted to make sure I was doing the correct thing. xp thanks!
Ah! Good idea to check your equation.
Can you check my work @Shalante I used the first equation I wrote for this:
A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?
Sorry, I was afk! :(
5.00*10^2 m / (1.00*10^2 km/h)
= 500 /(100 *1000/3600) m/(m/s)
= 5.000*3.600 s
= 18.00 s
= 18.0 s
Not sure how you got 19.8 m.
Also, the choice of the two ways to find the average velocity depends on the given information.