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BloomLocke367

  • one year ago

Okay, I have 2 kinesmatic equations written down to find the change in velocity... I don't know which one is correct or if they both are correct

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  1. BloomLocke367
    • one year ago
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    @mathmate you seem to know this stuff

  2. BloomLocke367
    • one year ago
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    I have |dw:1441317362885:dw| are they both correct?

  3. BloomLocke367
    • one year ago
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    They both are usable, right?

  4. anonymous
    • one year ago
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    Average velocity is equal to (initial velocity + final velocity)/2 Velocity is equal to distance/time Since final position-initial position is displacement and displacement is a distance. You are correct.

  5. BloomLocke367
    • one year ago
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    okay thank you XD I just wanted to make sure I was doing the correct thing. xp thanks!

  6. anonymous
    • one year ago
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    Ah! Good idea to check your equation.

  7. BloomLocke367
    • one year ago
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    mhm c:

  8. BloomLocke367
    • one year ago
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    Can you check my work @Shalante I used the first equation I wrote for this: A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?

  9. mathmate
    • one year ago
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    Sorry, I was afk! :( 5.00*10^2 m / (1.00*10^2 km/h) = 500 /(100 *1000/3600) m/(m/s) = 5.000*3.600 s = 18.00 s = 18.0 s Not sure how you got 19.8 m. Also, the choice of the two ways to find the average velocity depends on the given information.

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