BloomLocke367
  • BloomLocke367
Can you check my work @Shalante? A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance at \(5.00\times10^2\)m with an average speed of \(1.00\times10^2\)km/hr. How long would it take the cheetah to cover this distance at this speed? I first converted to m/s and I got the time to be 19.8s, is that right?
AP Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
BloomLocke367
  • BloomLocke367
I used |dw:1441319140411:dw|
anonymous
  • anonymous
I got 18.0 sec
BloomLocke367
  • BloomLocke367
how?

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More answers

BloomLocke367
  • BloomLocke367
I did 27.78m/s=550m/t. I then divided 550m by 27.78m/s and got 19.8s
anonymous
  • anonymous
\[\frac{ 100km }{ 1 hour }\times \frac{ 1000m }{ 1km }\times \frac{ 1hour }{ 60minutes }\times \frac{ 1minute }{ 60seconds }\]= 27.7m/s Notices 100km/1hr is the same as 100km/hr. 27.7m/s is velocity To get time=distance over velocity t=500m/27.7m/s=18.0s
anonymous
  • anonymous
It is 500m not 550m 5.00 x10^2m is 500m. Unless you posted the wrong number
anonymous
  • anonymous
Otherwise you did everything correct.
BloomLocke367
  • BloomLocke367
Uh oh... I typed the problem wrong. it is 5.50*10^2, not 5.00
BloomLocke367
  • BloomLocke367
thanks for pointing that out and making me double check xp
BloomLocke367
  • BloomLocke367
so am I correct?
anonymous
  • anonymous
Ah, I see. Yea you are correct then.
anonymous
  • anonymous
Nice job solving the problem.
BloomLocke367
  • BloomLocke367
thanks :)
anonymous
  • anonymous
Got anymore? I have 25 minutes before I go.
anonymous
  • anonymous
any more*
BloomLocke367
  • BloomLocke367
yes, there's a part b to that problem, I'm working it out right now
anonymous
  • anonymous
Feel free to post it, so I can solve it faster and also respond earlier.
BloomLocke367
  • BloomLocke367
it is "suppose the average speed of the cheetah were just 85.0km/hr. What distance would the cheetah cover during the same time interval calculated in a?"
BloomLocke367
  • BloomLocke367
I already converted it into m/s and got 23.61m/s
BloomLocke367
  • BloomLocke367
I got 467.5m... is that correct?
anonymous
  • anonymous
23.61m/s*19.8s=476.5m You are correct 4.74 x10^2m tho since we are multiplying and dividing and least sf in original value is 3. Brb let me switch computers. (In school)
BloomLocke367
  • BloomLocke367
oki c:
BloomLocke367
  • BloomLocke367
woe... why 4.74?
anonymous
  • anonymous
Oops I mean 4.76
anonymous
  • anonymous
Actually, it is better to round it off 467.5m becomes 467m. I was rushing when I shut down the computer lol. 2 mistakes already.
anonymous
  • anonymous
468m I mean.
BloomLocke367
  • BloomLocke367
hahaha it's alright.
anonymous
  • anonymous
If answer is in 4 sf then shortest sf is 3 then you do scientific notation Ex: 5067m is answer. Least sf is 3 5.07x10^3m
BloomLocke367
  • BloomLocke367
okay thanks for the tip XD I'll be right back, I'll be afk.
anonymous
  • anonymous
and shortest sf is 3, then you Typing so fast with this nice keyboard. Making lots of typos and such.
anonymous
  • anonymous
I had to go right now. Remember? Probably be back in like 90 minutes the least. Feel free to tag me or pm me later.
BloomLocke367
  • BloomLocke367
oki, I'm back now tho

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