Find x.

- anonymous

Find x.

- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

|dw:1441322195098:dw|

- anonymous

I'm kidding lol. To find this you need to figure out which one you're going to use. Sin, cos or tan?

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## More answers

- anonymous

Cos?

- anonymous

Nope. Remember cos is CAH and that would be the adjacent and hypotenuse. Which sides do they give you here?

- anonymous

Sin?

- anonymous

Yup. They give you the opposite and the hypotenuse here. Which is SOH
So the equation for this would be sin x = opposite/hypotenuse.

- anonymous

Would you like to identify the opposite and the hypotenuse?

- anonymous

x/12.1?

- anonymous

Yup. x would be the opposite and 12.1 would be the hypotenuse.
So now we figure out sin. Insert 36 into the calculator and press sin. You should get 0.587.
So now we have 0.587 = x/12.1
To solve this you need to multiply 12.1 on both sides to separate the x.
You should get 7.11.
Which is the missing side.
x = 7.11

- anonymous

Thank you so much! The number was really 39, but I tried it the same way you did it and I ended up getting 7.6 when rounded to one decimal place. Would that be correct?

- anonymous

Which number would really be 39? 12.1?

- anonymous

The 36 haha.

- anonymous

Ohh my bad lol

- anonymous

No worries.

- anonymous

Yes, that's correct. You would get 7.61 if the angle was actually 39 degrees haha. Well I think you got it! Good luck!

- anonymous

Thank you!

- anonymous

Would you mind telling me if I'm doing this one correct too?

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- anonymous

I'm doing sin 58= 4.0/x.

- anonymous

Yup that's correct. you're on the right track! Keep going.

- anonymous

So x=5?

- anonymous

I got 4.716 but it's pretty close..?

- anonymous

They would probably rather want your answer so thanks haha!

- anonymous

Haha anything else just tag me @TheChancellor

- anonymous

@TheChancellor Thank you so much. I'm sorry about all these questions. I'm taking a test and I really want to be sure that everything is correct. I have to recover my credits from my geometry class this past year so my school is making me take this online geometry course that has literally no correlation with the actual class I took lmao. I've never done trig before so it makes absolutely no sense to me that they would make me take a course with trig in it lol? And the lessons that the course gives are horrible so it's literally sink or swim for me when it comes to the tests lol. But anyway, to solve this one, would it just be 12/13=0.9?

##### 1 Attachment

- anonymous

No problem :o !
It's 12/13 = cosh 0.9
I think...

- anonymous

Nevermind,

- anonymous

Oh it's cos^-1. The inverse ^^

- anonymous

Got it. I have no clue how to do this one.

##### 1 Attachment

- anonymous

- anonymous

whoops sorry. I'm back.

- anonymous

@IDK So first what we know is AC = AD + DC
AD = AC - DC

- anonymous

|dw:1441327965682:dw|

- anonymous

Well we need to find the side length of the side BC first to find the whole triangle's base (AC)

- anonymous

You following?

- anonymous

Yup!

- anonymous

So we're going to find the opposite of triangle BCD

- anonymous

Opposite and adjacent, that's using tangent. So tan 40 = x/30

- anonymous

You should get 25.17 when you've solved for x. So the height of the triangle is 25.17

- anonymous

|dw:1441328488907:dw|

- anonymous

So rounded to the nearest whole number, would the answer be 25?

- anonymous

I suppose but we should keep it as a decimal right now since we're not finding BC.

- anonymous

Now we have to solve for the whole triangle. Hypotenuse is 60, Opposite is 25.17 and angle A is 30 degrees

- anonymous

Bear with me, I don't remember this too well :P
So we can use any sides/angles to find the whole adjacent... I will use 60 and 30 degrees.

- anonymous

So adjacent and hypotenuse ---> cos
cos 30 = adjacent/60

- anonymous

The whole length of the bottom side of the triangle once you've solved that would be 51.961 (apparently you didn't need to solve the other side but what do I know haha)
Now take 51.961 - 30

- anonymous

You should get 21.961... I think that should be AD. Do you understand what I did?

- anonymous

I think so. Now that I write it down I understand it more. Thank you.

- anonymous

Cheers. No problem! Keep at it and good luck.

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