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marigirl
 one year ago
write z=1  √3 i in polar form
I got my r = 2
and i got arg (theta) value as pi/3
marigirl
 one year ago
write z=1  √3 i in polar form I got my r = 2 and i got arg (theta) value as pi/3

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marigirl
 one year ago
Best ResponseYou've already chosen the best response.1the answer reads: (g) The modulus of 1  √3 i is √12 + (√3)2 = 2 and its argument θ satisfies tan θ =  √3/1 =  √3, whence θ is equal to either 2π/3 or 5π/3. Since y=√3 is negative, we have θ = 5π/3. The polar form of 3 + 3i is thus 2 (cos 5π/3 + i sin 5π/3). ....

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441322582245:dw Thats what i thought

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1this example too seems to be adding when i thought arg (theta) is positive \[\pi < \theta \le \pi \]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1unless im just confused.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that has to be the ugliest circle i have ever seen

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0correct answer though

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Umm no that's not a circle

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1I was trying to show that when the Arg theta value is between 0 and 180deg then it's positive

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441326450077:dw your point is in the 4th quadrant

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441326527937:dw

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Yes so should it be a negative and I got negative pi/3

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441326541656:dw

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Why haa the model answera added 3pi/2 to pi/3

freckles
 one year ago
Best ResponseYou've already chosen the best response.1it looks like they wanted you to write theta in between 0 and 2pi based on their answer

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so you just do pi/3+2pi

freckles
 one year ago
Best ResponseYou've already chosen the best response.1this will put you between 0 and 2pi

freckles
 one year ago
Best ResponseYou've already chosen the best response.1i see you wanted to add pi for some reason but that would put you in the second quadrant

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441326754891:dw doing theta+pi will put you in second quadrant as you can see

freckles
 one year ago
Best ResponseYou've already chosen the best response.1and we definitely want to be in 4th

freckles
 one year ago
Best ResponseYou've already chosen the best response.1theta+2pi would get us back there to fourth quadrant

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1If the question doesn't specify will pi/3 also be a sufficient answer

freckles
 one year ago
Best ResponseYou've already chosen the best response.1yes if they don't specify what they want theta between yes pi/3 will do and so would pi/3+2pi*n where n is an integer as long as you keep your r positive that is

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Also can u look at the image I have attached above...I guess they have demonstrated both methods

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[(r,\theta)=(r,\theta+2 \pi n) \\ \text{ or } \\ (r,\theta)=(r,\theta+\pi+2 \pi n)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1when it comes to polar coordinates there is not a unique way to express one point

freckles
 one year ago
Best ResponseYou've already chosen the best response.1not a unique way meaning there are infinite amount of ways to express one point

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so you could haven chosen (2,2pi/3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0on account of sine and cosine are periodic functions with period \(2\pi\)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1or (2,5pi/3) or (2,pi/3)
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