There are 10 ripe and 5 unripe bananas in a sack. Bananas are chosen one at a time, with replacment. What is the probability of choosing 2 unripe bananas and then 2 ripe bananas?
The answer is 4/81 but I'm having trouble on how they got it can anyone please explain it to me and help me understand it?
Stacey Warren - Expert brainly.com
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They did say. The probability of selecting an unripe banana each time is 1/3, and the probability of selecting a ripe banana each time is 2/3. But i still can't figure out how they got it.
The chance of getting unripe: 5/15 = 1/3
The chance of getting ripe: 10/15 = 2/3
2 unripe and 2 ripe:
(1/3)(1/3)(2/3)(2/3) = 4/81
Okay thank you I feel a little slow now. I would had never gotten that with out you're help!