There are 10 ripe and 5 unripe bananas in a sack. Bananas are chosen one at a time, with replacment. What is the probability of choosing 2 unripe bananas and then 2 ripe bananas? The answer is 4/81 but I'm having trouble on how they got it can anyone please explain it to me and help me understand it?

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There are 10 ripe and 5 unripe bananas in a sack. Bananas are chosen one at a time, with replacment. What is the probability of choosing 2 unripe bananas and then 2 ripe bananas? The answer is 4/81 but I'm having trouble on how they got it can anyone please explain it to me and help me understand it?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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They did say. The probability of selecting an unripe banana each time is 1/3, and the probability of selecting a ripe banana each time is 2/3. But i still can't figure out how they got it.
The chance of getting unripe: 5/15 = 1/3 The chance of getting ripe: 10/15 = 2/3 2 unripe and 2 ripe: (1/3)(1/3)(2/3)(2/3) = 4/81
Okay thank you I feel a little slow now. I would had never gotten that with out you're help!

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You're welcome :D

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