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FINALLY OS IS WORKING FOR ME. sorry for the delay

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that's just a rough sketch @mathmate can you help? I'm not sure because of the gap

I know what domain and range are xp

I have a test tomorrow and I'm doing a review sheet lol. I have half of it done xp

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yes I know something like that XD

but it's this particular graph that is bugging me

I'll help someone then. Pm me if you need further help.

I know how to write interval notation and using inequalities lol XD

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wouldn't it be [2,5)?

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Correction:
\([2,5)\cup(9,\infty)\)

So it's all clear how you would approach your particular problem?

yes I know...so would the domain be [-5,-1)U(3,+inf)?

The 3 in incorrect.
The point lies on the y-axis, so it's zero. 3 is the y-coordinate.

ooopppppppppsss. 0, I just realized that. sorry my sister was talking to me and I really can't focus

Note: all points on the y-axis have x-value=0.

Good, so you're all set!

Can't do the range, because there is not enough information.

yes I know XD I'm just frustrated. now how would I write that particular domain using equalities?

INequalities*** ugh

In set notation, you could write:
\(\{x | -5\le x < -1 \cup 0

It is possible for the range is the parabola vertex is actually at 3

if the parabola*

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Do you mean (-3,2) ?

and yes I do omg I just can't get ANYTHING right today. I'm so sorry :(

you use U if you have to glue together "separated" domains

So what do you propose for the range?

It's similar to the domain, but look along the y-axis.

it looks like [0,2] U (3,inf)

that's what I was about to say @phi. I had to refresh

Is that an endpoint at the right side of the graph?

and no, it's an arrow

so set notation would be {\({y~|~0\le y \le 2 U 3

right? or am I wrong? idek. I'm about to give up and go to bed

yes

thank you.