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BloomLocke367
 one year ago
Help? it says "Identify the xvalues of each discontinuity, and write if it is removable or not. If it is nonremovable then classify the type."
BloomLocke367
 one year ago
Help? it says "Identify the xvalues of each discontinuity, and write if it is removable or not. If it is nonremovable then classify the type."

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factor the denominator, then set it equal to zero and solve

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I have a graph D:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if one of the factors cancels with a factor in the numerator, then it is "removable" because you can remove it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh then it is even easier, you do it with your eyeballs instead of algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441327182915:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0course it would be much easier to help if we could see the picture :D

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I'm trying. give me a moment.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441327370892:dw

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0okay sorry it looks bad. the single point is at (1,1) and the open circle is at (1,3) and the other line runs between 2 and 3 on the xaxis. @satellite73

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the one with the hole is "removable" the other one isn't

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain why?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441327899031:dw The empty dot could have been a removable discontinuity, because we could have added a definition of the function for f(1)=3. However, since f(1) has been defined as 1, this discontinuity becomes nonremovable. x=2 is a vertical asymptote, which is a nonremovable discontinuity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441328135999:dw

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I am so confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one with the hole is removable cause you can remove it by filling in the hole

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one with an "infinite discontinuity" can't be adjusted to make it continuous, so it is not removable

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0which one is that? I'm sorry for so many questions but I don't understand

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Not everyone may agree with me, but according to the definition, a removable discontinuity is when a point (a hole) is undefined, in which case we can fill the hole and the function becomes continuous. (a hole is where the limit of the function from the left and right are defined and identical) However, in your case, the value of f(1) has been defined (f(1)=1), so we can no longer fill the hole (to make it continuous), so it is no longer removable.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0yes, I learned what it is and I'm looking at my notes right now and it just isn't making any sense at all.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0when it says to identify the xvalues, is it asking for the domain?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Please explain what bothers you.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0Just the question in general... what it's asking me to do

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1There are different kinds of discontinuities  removable discontinuities (where a hole interrupts an otherwise continuous curve)  essential discontinuities, which subdivides into  vertical asymptotes, and (as in x=3)  step discontinuities (a jump in yvalue) See: http://www.mathwords.com/e/essential_discontinuity.htm and http://www.mathwords.com/r/removable_discontinuity.htm The question is asking you to locate and identify the type of discontinuity in the given example.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I only learned continuous, removable discontinuity, jump discontinuity, and infinite discontinuity.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Well these are the same, but with a different name. continuous is not a discontinuity jump => step vertical asymptote =>infinite removable is where you can plug the "hole". In the given example, since f(1)=1, you can no longer plug the "hole" (1,3), so in my opinion, it becomes a jump discontinuity.
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