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jagr2713

  • one year ago

Someone Please HELP ASAP

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  1. anonymous
    • one year ago
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    Yes

  2. jagr2713
    • one year ago
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    Ok i am suppose to convert this into standard form \[y-4=\frac{ 1 }{ 4 }(x+5)\] and i did the distribute and got \[y-4=\frac{ 1 }{ 4 }x+\frac{ 5 }{ 4 }\]

  3. jagr2713
    • one year ago
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    Then i multiply 4 on both sides\[4(y-4)=4y-16\] \[4y-16=x+\frac{ 5 }{ 4 }\] then i know u add 16 but i cant put it into standard form from here.... It cant @Ashleyisakitty @satellite73

  4. jagr2713
    • one year ago
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    @freckles @mathmate @pooja195 Please help

  5. anonymous
    • one year ago
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    \[y-4=\frac{ 1 }{ 4 }(x+5)\] do not multiply out, multiply by 4 \[4y-16=x+5\]

  6. anonymous
    • one year ago
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    then put the variables on one side of the equal sign \[x-4y=21\]

  7. anonymous
    • one year ago
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    oops that is wrong

  8. anonymous
    • one year ago
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    \[x-4y=-21\] is better

  9. jagr2713
    • one year ago
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    \[\frac{ 1 }{ 4 }*5=\frac{ 5 }{ 4 }\]

  10. jagr2713
    • one year ago
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    @satellite73

  11. jagr2713
    • one year ago
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    @Luigi0210 @mathmate

  12. jagr2713
    • one year ago
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    Please help

  13. mathmate
    • one year ago
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    @satellite73 has already given the corrected answer as x−4y=−21 You can work with that.

  14. jagr2713
    • one year ago
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    i dont need the answer how did he get it.... look at my steps so see where i went wrong Pleaseeee

  15. mathmate
    • one year ago
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    ok, I'll do it in more detail.

  16. mathmate
    • one year ago
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    \(y-4=\frac{ 1 }{ 4 }(x+5)\) Cross multiply \(4(y-4)=x+5\) The standard form requires that all coefficients are integers, which we now satisfy. It is also preferable to express it with Ax+By=C, and A preferably positive. So we move all variables to the right (where x is positive) 4y-16=x+5 -16-5=x-4y -21=x-4y Without loss of generality, we switch sides, x-4y=-21, same as what @satellite73 got.

  17. jagr2713
    • one year ago
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    oh u didnt distribute the x and 1/4

  18. jagr2713
    • one year ago
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    @mathmate

  19. mathmate
    • one year ago
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    By cross-multiplying, I distribute on the left hand side 4(y-4) becomes 4y-16

  20. jagr2713
    • one year ago
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    OMG U MADE IT WAY MORE CLEARRRRR THANKS ALOT

  21. mathmate
    • one year ago
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    You're welcome! :)

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