1. anonymous

Yes

2. jagr2713

Ok i am suppose to convert this into standard form $y-4=\frac{ 1 }{ 4 }(x+5)$ and i did the distribute and got $y-4=\frac{ 1 }{ 4 }x+\frac{ 5 }{ 4 }$

3. jagr2713

Then i multiply 4 on both sides$4(y-4)=4y-16$ $4y-16=x+\frac{ 5 }{ 4 }$ then i know u add 16 but i cant put it into standard form from here.... It cant @Ashleyisakitty @satellite73

4. jagr2713

5. anonymous

$y-4=\frac{ 1 }{ 4 }(x+5)$ do not multiply out, multiply by 4 $4y-16=x+5$

6. anonymous

then put the variables on one side of the equal sign $x-4y=21$

7. anonymous

oops that is wrong

8. anonymous

$x-4y=-21$ is better

9. jagr2713

$\frac{ 1 }{ 4 }*5=\frac{ 5 }{ 4 }$

10. jagr2713

@satellite73

11. jagr2713

@Luigi0210 @mathmate

12. jagr2713

13. mathmate

@satellite73 has already given the corrected answer as x−4y=−21 You can work with that.

14. jagr2713

i dont need the answer how did he get it.... look at my steps so see where i went wrong Pleaseeee

15. mathmate

ok, I'll do it in more detail.

16. mathmate

$$y-4=\frac{ 1 }{ 4 }(x+5)$$ Cross multiply $$4(y-4)=x+5$$ The standard form requires that all coefficients are integers, which we now satisfy. It is also preferable to express it with Ax+By=C, and A preferably positive. So we move all variables to the right (where x is positive) 4y-16=x+5 -16-5=x-4y -21=x-4y Without loss of generality, we switch sides, x-4y=-21, same as what @satellite73 got.

17. jagr2713

oh u didnt distribute the x and 1/4

18. jagr2713

@mathmate

19. mathmate

By cross-multiplying, I distribute on the left hand side 4(y-4) becomes 4y-16

20. jagr2713

OMG U MADE IT WAY MORE CLEARRRRR THANKS ALOT

21. mathmate

You're welcome! :)