Someone Please HELP ASAP

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Someone Please HELP ASAP

Mathematics
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Ok i am suppose to convert this into standard form \[y-4=\frac{ 1 }{ 4 }(x+5)\] and i did the distribute and got \[y-4=\frac{ 1 }{ 4 }x+\frac{ 5 }{ 4 }\]
Then i multiply 4 on both sides\[4(y-4)=4y-16\] \[4y-16=x+\frac{ 5 }{ 4 }\] then i know u add 16 but i cant put it into standard form from here.... It cant @Ashleyisakitty @satellite73

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\[y-4=\frac{ 1 }{ 4 }(x+5)\] do not multiply out, multiply by 4 \[4y-16=x+5\]
then put the variables on one side of the equal sign \[x-4y=21\]
oops that is wrong
\[x-4y=-21\] is better
\[\frac{ 1 }{ 4 }*5=\frac{ 5 }{ 4 }\]
Please help
@satellite73 has already given the corrected answer as x−4y=−21 You can work with that.
i dont need the answer how did he get it.... look at my steps so see where i went wrong Pleaseeee
ok, I'll do it in more detail.
\(y-4=\frac{ 1 }{ 4 }(x+5)\) Cross multiply \(4(y-4)=x+5\) The standard form requires that all coefficients are integers, which we now satisfy. It is also preferable to express it with Ax+By=C, and A preferably positive. So we move all variables to the right (where x is positive) 4y-16=x+5 -16-5=x-4y -21=x-4y Without loss of generality, we switch sides, x-4y=-21, same as what @satellite73 got.
oh u didnt distribute the x and 1/4
By cross-multiplying, I distribute on the left hand side 4(y-4) becomes 4y-16
OMG U MADE IT WAY MORE CLEARRRRR THANKS ALOT
You're welcome! :)

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