A community for students.
Here's the question you clicked on:
 0 viewing
MoonlitFate
 one year ago
Three point charges are arranged on a line. Charge q3 = +5.00nC and is at the origin. Charge q2 = 2.50 nC and is at x = 4.00 cm . Charge q1 is at x = 1.50 cm .
What is q1 (magnitude and sign) if the net force on q3 is zero?
MoonlitFate
 one year ago
Three point charges are arranged on a line. Charge q3 = +5.00nC and is at the origin. Charge q2 = 2.50 nC and is at x = 4.00 cm . Charge q1 is at x = 1.50 cm . What is q1 (magnitude and sign) if the net force on q3 is zero?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F _{e}=k _{e}\frac{ q1q2 }{ r^2 }\] is the formula where \[k _{e}=8.9\times10^9\]

moonlitfate
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I was able to get that far. :) I am just not sure where I messed up. Let me see if I can post the work that I have already done...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441329766590:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So \[k _{e}\frac{ q2q3 }{ r^2 }+ k _{e}\frac{ q1q3 }{ r^2 }=0\] You know your values for all those variables except q1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441330202254:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[k _{e}(\frac{ q2q3 }{ r^2 }+\frac{ q1q3 }{ r^2})=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ q2q3 }{ r^2 }+\frac{ q1q3 }{ r^2 }=0\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.