mathbasedphysics question.
 idku
mathbasedphysics question.
 katieb
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 dan815
o goody
 idku
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 11 m/s at an angle 44 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.

2) What is the vertical component of the ball’s velocity right before Sarah catches it?
3) What is the time the ball is in the air?
 idku
I attempted (for question # 2) \(11\sin(44)\approx7.6\)m/s but it doesn't work when I enter it in my pracice thingy.
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 idku
The image would be this: http://i.imgur.com/TLF8qrM.png
 dan815
yep okay
 dan815
a complete parabollic motion completed in this throw okayq
 dan815
so the same vertical speed it started out with is the same speed it ended with
 dan815
dw:1441330388180:dw
 idku
Yes, so I tried 11sin(44) but it didn't work....
 idku
(well, I entered 7.64 approximation)
 dan815
its downward now so
 dan815
it will be negative 11*sin(44)
 idku
Oh, cool. Thanks, and how do I figure question #3?
 idku
3) What is the time the ball is in the air?
 dan815
okay now we dont really care about the horizontal component of the veloicty that is not going to determine how long the ball will stay up in the air
 dan815
What we need to worry about is the veloicty in Y and the acceleration in Y
 dan815
now lets break the problem into 2 symmetric parts,
the time it takes the ball to go up, and then the time it takes the ball once its all the way up to fall back down will be the same
 dan815
this is something you should prove to yourself when u have time
 dan815
so what we will do is figure out the time he takes from dw:1441330648992:dw
 idku
well, considering any vertex of (h,k) the vertical distance from (h,k) to (h,k+a) and the vertical distance from (h,k) to (h,ka) are same. ik that:)
 dan815
okay
 dan815
what is the speed at the top of the arc?
 dan815
the velocity / speed of the ball
 idku
I am just very unfamiliar with the formulas I have to apply at each time.
 dan815
no formulas needed
 idku
lol (?)
 dan815
what happens to the velocity at the very top
 idku
it is 0
 dan815
right
 dan815
so we started with
11sin(44)m/s and went to 0 m/s
now acecleration tells you how velocity changes wrt to time\
we have a constant acceleration of 9.8m/s^2
"9.8 m/s /s" we change 9.8m/s(speed) /s(per second)
 dan815
so if we went from /
11 sin(44) m/s to 0 m/s
how many second would that have took if every second we lose 9.8m/s
 idku
11sin(44)/9.81 seconds
 dan815
good :)
 dan815
now that is the time for half the motion right
 dan815
so multiply that time by 2 and ur done
 idku
I am really not that good to do logical conclusions like this on my own though. I think that practicing formulas at first and then comprehending to an extent of a logic would be better for me.....
Yes, multiply that by 2, so we got
2sin(44) (m/s)

9.81 (m/s^2)
and our units are seconds as well....
 idku
times 2, because we go from max vel to 0 velocity twice.
 dan815
2 * 11 *sin(44)/9.81
 idku
1.56 seconds
 dan815
probably right
 idku
Wolfram is always right:D
 dan815
:)
 idku
And how would I briefly go about the distance between the two girls?
 dan815
okay so we know the time it was up in the air
 dan815
now for that same time, it was constatly moving horizontally with that horizontal speed given 11 cos(44)
 idku
distance = time 5 velocity ?
 idku
oh, 5 was supposed to be ×
 dan815
yes thats right
 dan815
by definition speed is the change in distance per time unit
m/s
 idku
distance = 1.56 • 11cos(44) < that is our horizontal velocity
^

the time for vertical and horizontal is same.....
 dan815
yes
 idku
1.56s • 11cos(44)(m/s)
and units work too
 idku
12.34
 dan815
oh btw, you know how to you said youd rather pratice formulas to solve this, you should forget that way of thinking, it might even help you getting marks as far as highschool goes... but you will just be memorizing formulas and not understanding
 Jhannybean
\[\Delta x = v_{i_x}t + \frac{1}{2}gt^2\] can this work too? just wondering.
 idku
a=0 in horizontal force
 idku
because no gravity
 dan815
IF you want to do good in college, and get further in physics and other related stuff, you are better of understanding and trying to do this more logically
 idku
so just v•t
 dan815
eventually those people that are memorizing wont be able to solve the tougher problems
 idku
I am making sense out of it.... my prof is a good person but by no means can he be a teacher ... :(
tnx for helping me with it. I am kind of bad it (comparing to other subjects), but tnx!
 Jhannybean
dan is absolutely right
 dan815
dont worry it takes a while to get comfortable in physics
 dan815
i had one highschool teacher that gave us good advice, he said make sure you can picture the problem
 dan815
always do your best to picture the problems, really understand the question, understanding the questions is sometimes the most difficult part
 idku
Jhanny it is the teacher, I promise....
 idku
yes, understanding is best, because it is the only way to put it into memory
 Jhannybean
Many people do not like their physics professors, but its really in understanding what youre learning thats weighing you down, not the professor
 idku
I will have some more questions, and entire night to work on (waiting for friday 3pm after physics to chill). I have to ask more and do it..... sorry that I am stopping the conversation like this.
 idku
No, he doesn't explain he just derives formulas from formulas....
 idku
good luck, bye, apologize.
 Jhannybean
np :)
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