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idku
 one year ago
mathbasedphysics question.
idku
 one year ago
mathbasedphysics question.

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idku
 one year ago
Best ResponseYou've already chosen the best response.0Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 11 m/s at an angle 44 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.  2) What is the vertical component of the ball’s velocity right before Sarah catches it? 3) What is the time the ball is in the air?

idku
 one year ago
Best ResponseYou've already chosen the best response.0I attempted (for question # 2) \(11\sin(44)\approx7.6\)m/s but it doesn't work when I enter it in my pracice thingy.

idku
 one year ago
Best ResponseYou've already chosen the best response.0The image would be this: http://i.imgur.com/TLF8qrM.png

dan815
 one year ago
Best ResponseYou've already chosen the best response.2a complete parabollic motion completed in this throw okayq

dan815
 one year ago
Best ResponseYou've already chosen the best response.2so the same vertical speed it started out with is the same speed it ended with

idku
 one year ago
Best ResponseYou've already chosen the best response.0Yes, so I tried 11sin(44) but it didn't work....

idku
 one year ago
Best ResponseYou've already chosen the best response.0(well, I entered 7.64 approximation)

dan815
 one year ago
Best ResponseYou've already chosen the best response.2it will be negative 11*sin(44)

idku
 one year ago
Best ResponseYou've already chosen the best response.0Oh, cool. Thanks, and how do I figure question #3?

idku
 one year ago
Best ResponseYou've already chosen the best response.03) What is the time the ball is in the air?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2okay now we dont really care about the horizontal component of the veloicty that is not going to determine how long the ball will stay up in the air

dan815
 one year ago
Best ResponseYou've already chosen the best response.2What we need to worry about is the veloicty in Y and the acceleration in Y

dan815
 one year ago
Best ResponseYou've already chosen the best response.2now lets break the problem into 2 symmetric parts, the time it takes the ball to go up, and then the time it takes the ball once its all the way up to fall back down will be the same

dan815
 one year ago
Best ResponseYou've already chosen the best response.2this is something you should prove to yourself when u have time

dan815
 one year ago
Best ResponseYou've already chosen the best response.2so what we will do is figure out the time he takes from dw:1441330648992:dw

idku
 one year ago
Best ResponseYou've already chosen the best response.0well, considering any vertex of (h,k) the vertical distance from (h,k) to (h,k+a) and the vertical distance from (h,k) to (h,ka) are same. ik that:)

dan815
 one year ago
Best ResponseYou've already chosen the best response.2what is the speed at the top of the arc?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2the velocity / speed of the ball

idku
 one year ago
Best ResponseYou've already chosen the best response.0I am just very unfamiliar with the formulas I have to apply at each time.

dan815
 one year ago
Best ResponseYou've already chosen the best response.2what happens to the velocity at the very top

dan815
 one year ago
Best ResponseYou've already chosen the best response.2so we started with 11sin(44)m/s and went to 0 m/s now acecleration tells you how velocity changes wrt to time\ we have a constant acceleration of 9.8m/s^2 "9.8 m/s /s" we change 9.8m/s(speed) /s(per second)

dan815
 one year ago
Best ResponseYou've already chosen the best response.2so if we went from / 11 sin(44) m/s to 0 m/s how many second would that have took if every second we lose 9.8m/s

dan815
 one year ago
Best ResponseYou've already chosen the best response.2now that is the time for half the motion right

dan815
 one year ago
Best ResponseYou've already chosen the best response.2so multiply that time by 2 and ur done

idku
 one year ago
Best ResponseYou've already chosen the best response.0I am really not that good to do logical conclusions like this on my own though. I think that practicing formulas at first and then comprehending to an extent of a logic would be better for me..... Yes, multiply that by 2, so we got 2sin(44) (m/s)  9.81 (m/s^2) and our units are seconds as well....

idku
 one year ago
Best ResponseYou've already chosen the best response.0times 2, because we go from max vel to 0 velocity twice.

idku
 one year ago
Best ResponseYou've already chosen the best response.0Wolfram is always right:D

idku
 one year ago
Best ResponseYou've already chosen the best response.0And how would I briefly go about the distance between the two girls?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2okay so we know the time it was up in the air

dan815
 one year ago
Best ResponseYou've already chosen the best response.2now for that same time, it was constatly moving horizontally with that horizontal speed given 11 cos(44)

idku
 one year ago
Best ResponseYou've already chosen the best response.0distance = time 5 velocity ?

idku
 one year ago
Best ResponseYou've already chosen the best response.0oh, 5 was supposed to be ×

dan815
 one year ago
Best ResponseYou've already chosen the best response.2by definition speed is the change in distance per time unit m/s

idku
 one year ago
Best ResponseYou've already chosen the best response.0distance = 1.56 • 11cos(44) < that is our horizontal velocity ^  the time for vertical and horizontal is same.....

idku
 one year ago
Best ResponseYou've already chosen the best response.01.56s • 11cos(44)(m/s) and units work too

dan815
 one year ago
Best ResponseYou've already chosen the best response.2oh btw, you know how to you said youd rather pratice formulas to solve this, you should forget that way of thinking, it might even help you getting marks as far as highschool goes... but you will just be memorizing formulas and not understanding

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\Delta x = v_{i_x}t + \frac{1}{2}gt^2\] can this work too? just wondering.

dan815
 one year ago
Best ResponseYou've already chosen the best response.2IF you want to do good in college, and get further in physics and other related stuff, you are better of understanding and trying to do this more logically

dan815
 one year ago
Best ResponseYou've already chosen the best response.2eventually those people that are memorizing wont be able to solve the tougher problems

idku
 one year ago
Best ResponseYou've already chosen the best response.0I am making sense out of it.... my prof is a good person but by no means can he be a teacher ... :( tnx for helping me with it. I am kind of bad it (comparing to other subjects), but tnx!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dan is absolutely right

dan815
 one year ago
Best ResponseYou've already chosen the best response.2dont worry it takes a while to get comfortable in physics

dan815
 one year ago
Best ResponseYou've already chosen the best response.2i had one highschool teacher that gave us good advice, he said make sure you can picture the problem

dan815
 one year ago
Best ResponseYou've already chosen the best response.2always do your best to picture the problems, really understand the question, understanding the questions is sometimes the most difficult part

idku
 one year ago
Best ResponseYou've already chosen the best response.0Jhanny it is the teacher, I promise....

idku
 one year ago
Best ResponseYou've already chosen the best response.0yes, understanding is best, because it is the only way to put it into memory

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Many people do not like their physics professors, but its really in understanding what youre learning thats weighing you down, not the professor

idku
 one year ago
Best ResponseYou've already chosen the best response.0I will have some more questions, and entire night to work on (waiting for friday 3pm after physics to chill). I have to ask more and do it..... sorry that I am stopping the conversation like this.

idku
 one year ago
Best ResponseYou've already chosen the best response.0No, he doesn't explain he just derives formulas from formulas....

idku
 one year ago
Best ResponseYou've already chosen the best response.0good luck, bye, apologize.
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