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BloomLocke367

  • one year ago

How do I create a table of values to determine the behavior of a graph at the vertical asymptotes?

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  1. BloomLocke367
    • one year ago
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    @mathmate

  2. BloomLocke367
    • one year ago
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    @Shalante

  3. anonymous
    • one year ago
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    Can be done by using limits. Since DNE at x=(VA), use numbers very close to each side of the VA. Hope that helps a little?

  4. BloomLocke367
    • one year ago
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    the v. asymptote is at x=-1 and the function is \(f(x)=\frac{2x-3}{x+1}\)

  5. anonymous
    • one year ago
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    Plug and chug values close to the asymptotes You never took calculus right?

  6. BloomLocke367
    • one year ago
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    right @Shalante

  7. anonymous
    • one year ago
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    Yea that is basically it. x=-1 is undefined. Plug like -1.0001 and -1.01 and -0.999& -0.98 Understood?

  8. anonymous
    • one year ago
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    Oh dang, got to go now.

  9. BloomLocke367
    • one year ago
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    okay..okay. I'll do that. then it says to use limit notation to explain the behavior. I know what limit notation is...but I don't know the behavior

  10. BloomLocke367
    • one year ago
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    dang, ok. thanks for your help

  11. anonymous
    • one year ago
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    Just plug values to the left and right of the equation. It should tell you.

  12. BloomLocke367
    • one year ago
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    ok

  13. mathmate
    • one year ago
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    |dw:1441331980524:dw|

  14. mathmate
    • one year ago
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    The reason you need to plot is to see if it goes + or - infinity, from the left or from the right.

  15. mathmate
    • one year ago
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    And you're expected to identify the value of x where the vertical asymptote occurs. This you can do by checking at what point the denominator vanishes.

  16. BloomLocke367
    • one year ago
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    okay. I made my table and now I need to use limit notation to express the behavior.

  17. BloomLocke367
    • one year ago
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    and I understand that part @mathmate

  18. BloomLocke367
    • one year ago
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    and I already got the horizontal asymptote.. it's y=2. Now all I need is that one part

  19. mathmate
    • one year ago
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    Yes, horizontal asymptote is 2, from Lim 2x/x. (even though this particular question did not ask for it).

  20. BloomLocke367
    • one year ago
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    actually it did XD I just didn't write it

  21. BloomLocke367
    • one year ago
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    OOOH I THINK I KNOW WHAT IT MEANS. do I write it in limit notation as it approaches the v. asymptote?

  22. BloomLocke367
    • one year ago
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    I got it. I only have one more c: I'll open a new question and tag you

  23. mathmate
    • one year ago
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    ok!

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