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BloomLocke367
 one year ago
How do I create a table of values to determine the behavior of a graph at the vertical asymptotes?
BloomLocke367
 one year ago
How do I create a table of values to determine the behavior of a graph at the vertical asymptotes?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can be done by using limits. Since DNE at x=(VA), use numbers very close to each side of the VA. Hope that helps a little?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0the v. asymptote is at x=1 and the function is \(f(x)=\frac{2x3}{x+1}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug and chug values close to the asymptotes You never took calculus right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea that is basically it. x=1 is undefined. Plug like 1.0001 and 1.01 and 0.999& 0.98 Understood?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh dang, got to go now.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0okay..okay. I'll do that. then it says to use limit notation to explain the behavior. I know what limit notation is...but I don't know the behavior

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0dang, ok. thanks for your help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just plug values to the left and right of the equation. It should tell you.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441331980524:dw

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0The reason you need to plot is to see if it goes + or  infinity, from the left or from the right.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0And you're expected to identify the value of x where the vertical asymptote occurs. This you can do by checking at what point the denominator vanishes.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0okay. I made my table and now I need to use limit notation to express the behavior.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0and I understand that part @mathmate

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0and I already got the horizontal asymptote.. it's y=2. Now all I need is that one part

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Yes, horizontal asymptote is 2, from Lim 2x/x. (even though this particular question did not ask for it).

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0actually it did XD I just didn't write it

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0OOOH I THINK I KNOW WHAT IT MEANS. do I write it in limit notation as it approaches the v. asymptote?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I got it. I only have one more c: I'll open a new question and tag you
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