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sissyedgar
 one year ago
What is 4.6 × 10^8 cm/min in meters per hour?
A.
2.76 × 10^8 m/h
B.
2.76 × 10^10 m/h
C.
7.67 × 10^6 m/h
D.
7.67 × 10^8 m/h
sissyedgar
 one year ago
What is 4.6 × 10^8 cm/min in meters per hour? A. 2.76 × 10^8 m/h B. 2.76 × 10^10 m/h C. 7.67 × 10^6 m/h D. 7.67 × 10^8 m/h

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sissyedgar
 one year ago
Best ResponseYou've already chosen the best response.0@amirreza1870 @Shalante

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0need 2 step conversion

sissyedgar
 one year ago
Best ResponseYou've already chosen the best response.0right, cm to meter min 2 hour

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0cm to m and min to hr

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0it does not matter which one you do first but pay attention to the conversion factor

sissyedgar
 one year ago
Best ResponseYou've already chosen the best response.01 hour = 60 minutes

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I would do min to hr first

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0remember when you multiply numbers with the same base add the exponents when you divide numbers with the same base subtract the exponents

sissyedgar
 one year ago
Best ResponseYou've already chosen the best response.0still dont kno wat 2 do 1st in converision! @Shalante

Jack1
 one year ago
Best ResponseYou've already chosen the best response.04.6 × 10^8 cm/min \(\Large= \frac{4.6 × 10^8 ~cm}{1~ min} \) so first: convert from minutes to hours \(\Large= \frac{4.6 × 10^8 ~cm}{1~ min} ~ \times ~ \frac {60~mins}{1~hr}~ =~ \frac {4.6 × 10^8 × 60 ~cm}{1~hr}\) now you have an answer in cm per hour... so convert this to centimeters to meters \(\Large= \frac {4.6 × 10^8 × 60 ~cm}{1~hr} ~ \times ~ \frac {1~m}{1000~cm}~ =~ \frac {4.6 × 10^8 × 60 ~m}{1000~hrs}\) now expand it out: \(\Large= \frac {4.6 × 10^8 × 60 ~m}{1000~hrs} = \frac {27600000000~m}{1000~hrs}\) now reduce it down to scientific notation... can you do that from here?
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