Please help me with 2 brief questions.

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Please help me with 2 brief questions.

Mathematics
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A cannonball is shot (from ground level) with an initial horizontal velocity of 33 m/s and an initial vertical velocity of 25 m/s. ------------------------------------------------------------ \(\rm \large I~found~so~far:\) [1] initial speed, \(\rm u=41.4(m/s)\) [2] angle of cannonball with respect to ground, \(\rm \theta=37.15º\) [3] maximum height the cannonball goes above the ground \(\rm x=31.8(m)\) [4] horizontal displacement is \(\rm 167.6(m)\) [5] the entire time of the ball motion \(\rm 5.1(s)\) ------------------------------------------------- \(\rm \large I~need:\) [6] speed of the cannonball at, \(\rm t=3.7(s)\) [7] height (Vertical Displacement) at, \(\rm t=3.7(s)\)
6.Vi = √[Vx²+Vy²] = 44.2 m/s 7.3) Hmax = Vi²sin²Θ/(2g) = 62.49 m
Are you sure? Becsause that doesn't seem to be right.

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Don't know,I never liked physics. Maybe he can help @Hero @dan815 @iambatman
I found the vertical displacement x=25.35m applying: \(x = ut + \dfrac{1}{2}at^2\) I have put: t=3.7s a=-9.81m/s\(^2\) u=25m/s
Nice.
I need velocity at t=3.7 the rest i found. tnx for coming btw
Your welcome!
A cannonball is shot (from ground level) with an initial horizontal velocity of 33 m/s and an initial vertical velocity of 25 m/s. [6] speed of the cannonball at, t=3.7(s) [7] height (Vertical Displacement) at, t=3.7(s)
[7]=25.35m found that:)
|dw:1441344582144:dw|
speed is the magnitude of velocity
velocity tells you how speed is broken into components of direction
\(\large V_y=25-9.81(3.7)=-11.297\) \(\large V_x=33\) (yes, it doesn't change b/c acceleration is 0) \(\large V_t=\sqrt{33^2+11.297^2}=34.88\)
yeah
|dw:1441344791089:dw|
oh, that is what I wanted to do. to use pythagorean theoream after fiding vert and horiz velocities (well horiz veloc I knew...:D) I was getting NEGATIVE 11.297 so I was thinking it is wrong.
I mean those veloc at t=3.7
negative velocity just means down, it an indication of direction thats all
I will take a note of that in my brain. Ok, so negative velocity is also an acceptable result (unlike displacement)
to someone who flipped the page, he will think the Veocity is positive it doesnt matter to him its the way u chose your coordinates
I want to flip the page, but another page. The page of the physics intersecting w/ my life.... I don';t even know what I would do without you
LOL
get used to it, uve intersected with physics from the day u were born
yes, but not with due dates
and not with rediculous teachers such as my prof at college
xD
In any case, I guess - Alright. I have a report on a lab. That I should be able to do. (Got 6 hours to work on it before my next classes)
Have a good night or where ever yo are. Niagara falls:D

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