anonymous
  • anonymous
what are the coordinates of the focus of the conic section shown below? y^2+16y-4x+4=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@ShirouxGhoul
triciaal
  • triciaal
start by completing 2 squares x's and y's
triciaal
  • triciaal
did you skip a term with x^2?

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anonymous
  • anonymous
can you go through the steps please? im really confused
triciaal
  • triciaal
|dw:1441343632292:dw|
anonymous
  • anonymous
Got it, or more explanation?
triciaal
  • triciaal
|dw:1441343759380:dw|
anonymous
  • anonymous
the answer was actually (-14,-8)
anonymous
  • anonymous
but thank you anyways to both of you!! :)
anonymous
  • anonymous
Really?? Your welcome!
welshfella
  • welshfella
y^2 + 16 = 4x - 4 completing the square (y + 8)^2 - 64 = 4x - 4 (y + 8)^2 = 4x + 60= 4(x + 15) compare with standard form (y - k)^2 = 4a(x - h) vertex is at (-15,-8) 4a = 4 so a = 1 focus is at (-15+1, -8) = (-14,-8)

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