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anonymous
 one year ago
what are the coordinates of the focus of the conic section shown below?
y^2+16y4x+4=0
anonymous
 one year ago
what are the coordinates of the focus of the conic section shown below? y^2+16y4x+4=0

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.0start by completing 2 squares x's and y's

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0did you skip a term with x^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you go through the steps please? im really confused

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441343632292:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Got it, or more explanation?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441343759380:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer was actually (14,8)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but thank you anyways to both of you!! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really?? Your welcome!

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0y^2 + 16 = 4x  4 completing the square (y + 8)^2  64 = 4x  4 (y + 8)^2 = 4x + 60= 4(x + 15) compare with standard form (y  k)^2 = 4a(x  h) vertex is at (15,8) 4a = 4 so a = 1 focus is at (15+1, 8) = (14,8)
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