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steve816

  • one year ago

Please help, I'm stuck at 4 AM doing math!

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  1. steve816
    • one year ago
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    Solve in the complex number system: \[x^2+3=x\]

  2. zzr0ck3r
    • one year ago
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    \(x^2-x+3=0\implies (x-\dfrac{1}{2})^2=-3+(\dfrac{1}{2})^2\\(x-\dfrac{1}{2})^2=\dfrac{-11}{4}\)

  3. zzr0ck3r
    • one year ago
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    Can you complete here?

  4. steve816
    • one year ago
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    Is completing the square the only method or was I allowed to use the quadratic formula?

  5. steve816
    • one year ago
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    I can finish off from here, thanks for the help :)

  6. zzr0ck3r
    • one year ago
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    sure, you can use that. This was just faster...

  7. zzr0ck3r
    • one year ago
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    The quadratic equation is derived using the "completing the square" method :)

  8. steve816
    • one year ago
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    Oh really? Never really understood how the quadratic equation worked even though i'm in pre-calculus.

  9. zzr0ck3r
    • one year ago
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    \[ax^2+bx+c=0\\a(x^2+\frac{b}{a}x)=-c\\a(x+\dfrac{b}{2a})^2=-c+a\dfrac{b^2}{4a^2}\\(x+\dfrac{b}{2a})^2=\frac{-c}{a}+\frac{b^2}{4a^2}\\(x+\dfrac{b}{2a})^2=\dfrac{b^2-4ac}{4a^2}\\(x+\dfrac{b}{2a})=\pm \sqrt{\dfrac{b^2-4ac}{4a^2}}\\(x+\dfrac{b}{2a})=\pm \dfrac{\sqrt{b^2-4ac}}{2a}\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\]

  10. steve816
    • one year ago
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    Holy guacamole! :o *jaw drops*

  11. wolf1728
    • one year ago
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    Here's another explanation of deriving the quadratic formula: http://www.1728.org/quadr2.htm

  12. zzr0ck3r
    • one year ago
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    pretty much the same way.

  13. wolf1728
    • one year ago
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    steve - did you check that answer?

  14. wolf1728
    • one year ago
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    the (-11/4) answer?

  15. steve816
    • one year ago
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    Yup, I got the answer right.

  16. anonymous
    • one year ago
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    The answer is (-11/4)

  17. steve816
    • one year ago
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    that wasn't the answer... @lauren.ascough

  18. wolf1728
    • one year ago
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    I don't get that answer a=1 b=-1 c=3 right?

  19. anonymous
    • one year ago
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    Yeah

  20. wolf1728
    • one year ago
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    x = 1 +- sq root(1 -4*1*3) / 2 x = [1 +- sq root(-11)] / 2

  21. steve816
    • one year ago
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    yeah, that is what I got.

  22. wolf1728
    • one year ago
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    Okay, it's just that I didn't see that answer printed anywhere.

  23. steve816
    • one year ago
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    Thanks for the answer though.

  24. anonymous
    • one year ago
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    Im stuck at 6AM playing and modding skyrim Why? BECAUSE IM IN VIRTUAL SCHOOL

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