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Abhisar

  • one year ago

An electron is moving at \(\sf 10^6\) m/s in a direction parallel to a current of 5A flowing through an infinite long straight wire separated by a perpendicular distance of 0.1 m in air. Magnetic force experienced by the electron will be?

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  1. Abhisar
    • one year ago
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    This is how I am doing.... The field due to the infinite current wire at any point at a perpendicular distance of 0.1m from it can be calculated by ampere's law as, \(\sf B=\Large \frac{5 \times 2\mu_0}{4\pi\times 0.1}=10^2\times 10^{-7}=10^{-5}\) Now, magnetic force can be calculated as, \(\sf \vec{F_m}=q(\vec{V}\times \vec{B})\\ \Rightarrow 1.6\times 10^{-19}(10^6\times 10^{-5}\times sin(90^0))=1.6 \times 10^{-18}\)

  2. Rushwr
    • one year ago
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    Ur methods are correct I suppose ! Still having a slight doubt on the 1st part . Applying of F=BqV is alright. What's the answer given ?

  3. Abhisar
    • one year ago
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    Answer is different doe, the key says \(\sf 4 \times 10^{-11}\) N :(

  4. Abhisar
    • one year ago
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    Whoops... Wait !! The answer is \(\sf 1.6 \times 10^{-18}\)N. All this time I was looking answer for different question :D.

  5. Rushwr
    • one year ago
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    lol

  6. Rushwr
    • one year ago
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    ok then

  7. Abhisar
    • one year ago
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    Thnx doe c:

  8. Rushwr
    • one year ago
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    lol no problem

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