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ghdoru11
 one year ago
Find the Fourier expansion for: f:R>R periodic T=2pi , f(x)=3x, x is between [pi,pi]
ghdoru11
 one year ago
Find the Fourier expansion for: f:R>R periodic T=2pi , f(x)=3x, x is between [pi,pi]

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beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.3Why was this question closed?

ghdoru11
 one year ago
Best ResponseYou've already chosen the best response.0no one solve this and i have another question

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.3Anyway you can just go back to the definition of fourier coefficients: \[a_n = \int_{\pi}^{\pi} 3x*sin(nx)dx\] \[b_n = \int_{\pi}^{\pi} 3x*cos(nx)dx\] then evaluate the integrals. Use the substitution t = nx and integration by parts with u being the linear term and v' the trigonometeric part.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1yeah, and it's odd so you ignore the cosine term

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.3Right, that saves a lot of work :)

ghdoru11
 one year ago
Best ResponseYou've already chosen the best response.0so just the first integral is neded?

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.3Yes, \(b_n\) = 0 for every n.

ghdoru11
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much guys
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