## anonymous one year ago Suppose there are 15 jelly beans in a box (2 red, 3 blue, 4 white, and 6 green). A jelly bean is selected at random. What is the probability that the jelly bean is neither red nor blue?

1. Nnesha

total : 15 take out the red and blue how many jellybeans would you have left ?

2. anonymous

10

3. Nnesha

$\frac{ 15-(\color{ReD}{2}+\color{blue}{3}) }{ 15 }$ yes right!

4. anonymous

so would it be 10/15 = 2/3 in lowest terms?

5. Nnesha

yes right!

6. anonymous