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anonymous
 one year ago
What value of w makes the mean of R as large as possible? What is the SD of R for this value of w?
What is the value of w that minimizes the SD of R?
anonymous
 one year ago
What value of w makes the mean of R as large as possible? What is the SD of R for this value of w? What is the value of w that minimizes the SD of R?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$1 in a stock yeilds Rs, $1 in a bond yeilds Rb Rs is random with a mean .08 and SD of .07 Rb is random with a mean .05 and SD of .04 Correlation of Rs and Rb is .25 If you place a fraction w of your money in the stock fund and the rest, 1w, in the bond fund, then your return on you investment is R=wRs+(1w)Rb SD(R)=sqrt(0.0051((w)^2)0.0018W+0.0016) E(R) = 0.05 + 0.03w

phi
 one year ago
Best ResponseYou've already chosen the best response.2w makes the mean of R as large as possible? I think that is the same as maximize the expected value E(R) = 0.05 + 0.03w If that equation is correct, then w=1 maximizes. it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah that's the correct answer! I can see why, intuitively. Can you explain why taking the derivative doesn't bring us to that, though? Kind of confused. Wouldn't taking the derivative and setting = 0 maximize? Or am I misremembering my calculus hahaha

phi
 one year ago
Best ResponseYou've already chosen the best response.2E(R) = 0.05 + 0.03w is an equation of a line y= mx + b y = 0.03x + b the derivative dy/dx = 0.03 gives you the slope of the line *if* a curve has a changing slope e.g. \( \cap\) , then perhaps there is a point where the slope is zero, and that signals a possible min, max or inflection pt. that idea does not work for a line. the other criteria for a min/max is to evaluate any boundary conditions in this case, w has values from 0 to 1. test those values.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay sweet thanks for the clarification. For what is the value of w that minimizes the SD of R test 0,1 and then see if there's any critical points w/ derivative = 0, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mind checking my answer when I get it? Give me a second. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well the answer is x=3/17, not sure the easiest way to come to that though. Is there an easier way than taking the derivative and =0? The derivative is a little ugly

phi
 one year ago
Best ResponseYou've already chosen the best response.2the derivative is \[ \frac{2aw+b}{2\sqrt{aw^2+bw+c} }=0\] clearing the denominator: 2aw+b=0 \[ w= \frac{b}{2a} \] where a= 0.0051, b= 0.0018, c=0.0016 thus you get \[ w= \frac{0.0018}{0.0102} = \frac{18}{102} = \frac{3}{17} \]
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