- anonymous

What is the equation of the line, in point slope form, that passes through the given point and has the given slope? point: (8,-8) and slope 3
a. y-8=3(x+8)
b. y+8=3(x+8)
c. y-8=3(x-8)
d. y+8=3(x-8)
What are the intercepts of the equation?
5x+3y=15
what is the equation of the line perpendicular to the line y= 4/9 x - 2 that passes through point (4,3)
a. y= -4/9 x -2
b. y= 9/4 x + 6
c. y= -9/4 x + 12
d. y= -9/4 x - 12
i really need help, please help

- katieb

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- LynFran

ok lets start with the first question

- anonymous

okay

- LynFran

we are given points (8,-8) and slope 3
to put in point slope form|dw:1441393907189:dw|

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## More answers

- anonymous

so would i distribute ?

- LynFran

yes

- LynFran

only the negative sign

- LynFran

which option would we get?

- anonymous

hold on oneee second im almost done

- anonymous

wait so for y-(-8) how woould i distribute that, would it be just be -8y?

- LynFran

|dw:1441394211850:dw|

- anonymous

so it would be 8y= 3x - (-) 24?

- LynFran

no ... u just need to distbute the 2 negative signs here|dw:1441394401381:dw|

- anonymous

ohhhhhh okay

- LynFran

i this case to match the given options
the 2 negatives will make positive when....

- LynFran

so 1st question answer??

- anonymous

its y+8 = 3 (x-8) so D

- LynFran

yes

- anonymous

thank you

- anonymous

what is the equation of the line perpendicular to the line y= 4/9 x - 2 that passes through point (4,3)
Refer to the attachment from Mathematica.

##### 1 Attachment

- anonymous

i dont understand that @robtobey

- LynFran

question 2
intercepts
to find the x-intercept we let y=0
to find the y-intercept we let x=0
but first we solve the given equation..
5x+3y=15
lets solve for y
3y=15-5x
y=(-5x+15)/3
now find the x intercept....
0=(-5x+15)/3

- anonymous

you took the 3 away from y to solve for it butbwhy did you put it into the equation to divide. dont we cancel something out?

- LynFran

since the 3 was being multiplied to y....3y ...to get the y term alone we divide by 3...and since its an equation...what we do to the left side we must do the same to the right side ...

- anonymous

ohh okay okay i gotchu

- LynFran

so wats the x-intercept?

- anonymous

0?

- LynFran

nope

- anonymous

3?

- LynFran

0=(-5x+15)/3

- anonymous

i give up

- LynFran

0*3=(-5x+15)/3*(3)...the 3 will cancel on the right side
0=-5x+15
0+5x=-5x+5x+15
5x=15
x=15/5
x=3
the x-intercept (3,0)

- anonymous

okay i understand it better i guess its still a little confusing but ill look over some more later

- LynFran

lets solve the y-intercept
y=(-5(0)+15)/3
y=(0+15)/3
y=15/3

- LynFran

so the y-intercept is?

- anonymous

would it be 5

- LynFran

plz put it in point form

- LynFran

like (x,y)

- anonymous

okay soo (0,5)

- LynFran

yes

- anonymous

yayy

- LynFran

Do u want me to do the 3rd question...or..its ok...

- anonymous

yeah because the way that guy did it really confused me

- LynFran

ok when two lines are perpendicular their slopes=-1
in other words the product of there slope =-1

- LynFran

our equation y=4/9x-2 with point (4,3)

- LynFran

can u tell me the slope for that equation

- anonymous

no because i have no clue whats going on

- LynFran

y=mx+b
where m is the slope and b is the y-intercept

- anonymous

m is 4/9x and b is -2?

- LynFran

m=4/9

- LynFran

so |dw:1441396731186:dw|

- LynFran

whats our new slope?

- anonymous

would it be -4/9?

- LynFran

|dw:1441396920476:dw|

- LynFran

|dw:1441397063320:dw|

- anonymous

so it would be -9/4x

- LynFran

so we have our new slope m=-9/4 and points (4,3)

- anonymous

would the answer be c?

- LynFran

yes

- LynFran

do u have any question?....

- anonymous

no, thank you so much for helping me !!!

- LynFran

ok welcome

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