HELP PLEASE!! As the second hand of the clock rotates the large gear turns 40 degrees. AE = 7 inches, and CD = 5 inches. AC, the length of the chain between the gears is 23 inches. How far does the chain around the circumference of the large gear move to the nearest tenth of an inch? (Enter only the number.)

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HELP PLEASE!! As the second hand of the clock rotates the large gear turns 40 degrees. AE = 7 inches, and CD = 5 inches. AC, the length of the chain between the gears is 23 inches. How far does the chain around the circumference of the large gear move to the nearest tenth of an inch? (Enter only the number.)

Mathematics
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CAN SOMEONE EXPLAIN IT STEP BY STEP PLEASE?

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okay so
the chain is dragged along the smaller gear as it turns 40 degrees
what is the distance the chain moved?
|dw:1441399747422:dw|
so u see the arc length of that thing
|dw:1441399865127:dw|
can you find the arc length?
hint the circumferece of the whole circle is 2pi*r thats for 360 degrees so for 40 degrees how much should it be
I still dont understand it!
okay lets start with the smaller piece all by itself
ok
|dw:1441400103489:dw|
x is that arc length for 40 degrees
this is confusing im sorry
how about the circumference of the circle do you know that formula
2pi*r
right okay plug in for radius
what si the whole circumferece of the small circle?
251.33?
31.42?
ya ist 10pi so 31.42 approximately
now 40 degrees is what fraction of 360
if you split 360 into parts of 40
9
right so 40 is 1/9th of 360
you can also split the circumference which belong to the 360 degrees in 9 ways so u can see how much of that circumference belongs to each 40 degrees
1/9th of 31.42 = length of x
to write it with our rounding its 10pi/9
without rounding
|dw:1441402206061:dw|
40
31.4
she will teach you
ok
youre pretty much done, you found x, right?
is x 31.4?
i'm not sure if this answer is right but is it 4.9? @Jhannybean @dan815

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