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i'm in
i'd give it a good hard slap with a Laplace Transform, but there are probably other ways too.

i tried using the homogenous solution and the particular solution but i can't figure it out

so first you solved
\[ y''-3y'+2y=0\]
and you got an answer?

then you turned your mind to
\[y''-3y'+2y=x \ e^x\]

another way, a bit quicker

Your writing is a little messy!

it's deliberate! it's all a load of rubbish really, i just made it up and posted it :-))

@IrishBoy123 all you done there is the solve or just a part of it?

thank you for your time, now it's clear to me. hope i will pass the exam