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Meehan98
 one year ago
I need help with writing molecular equations.
The original question states, "Write the balanced net ionic equation that occurs when copper (II) chloride and potassium phosphate react in water." The first step is to write the balanced molecular equation, and that is what I struggle with. I will type the equation that I have so far in the comments.
Meehan98
 one year ago
I need help with writing molecular equations. The original question states, "Write the balanced net ionic equation that occurs when copper (II) chloride and potassium phosphate react in water." The first step is to write the balanced molecular equation, and that is what I struggle with. I will type the equation that I have so far in the comments.

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Meehan98
 one year ago
Best ResponseYou've already chosen the best response.0\[Cu ^{2+}Cl _{2}^{} + K _{3}^{+} PO _{4}^{2}\rightarrow Cu(PO _{4}) + K _{3} Cl _{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Close, but phosphate is \[PO _{4}^{3}\] making your potassium incorrect also.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A molecular equation shows no ion (charges).

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.0The final solution to the molecular equation is: \[3CuCl _{2} + 2 K _{3} PO _{4}\rightarrow 6 KCl + Cu _{3} (PO _{4})_{2}\] I don't understand how to balance the equation to receive this answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You balanced it correctly! Nice!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait, you just saw the answer but did not attempt it successfully?

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I have the answer, but I don't know what to do in order to get to that balanced equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is my way. Count the number and write on both sides. Start both of each element and put it on the left side. I will put a number next to the ones in the left by separating it with a comma. Left side (reactants) Right side(Products) 1,3 Cu 3 2,6 Cl 1,6 3,6 K 1,6 1,2 P 2 4,8 O 8 Now lets start and try to make it equal by multiplying. There is more Cu in the right so multiply the left side where Cu is at by 3. There I would put the comma followed by 3. But that would make Cl 6, so I put a comma next to the 2 in Cl, then put 6 Next multiply the Cl in the right side by 6. That makes six K also Multiply K by 2 in the left side to make it equal That would make two P and eight O. See. It all equals out. You just need practice. No easier way then practice.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(The number of elements before), (the number of each elements after multiplying it)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is pretty confusing at first, but do you know what is true for an equation to be balanced?

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.0Okay, this helped immensely!!! Thank you! Yes, the elements must have the same number on each side of the equation in order for it to be balanced.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Glad you understood! Good luck!
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