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anonymous
 one year ago
HELP PLEASE!!!!!!
I know the answer I just need to know about the exponents...
anonymous
 one year ago
HELP PLEASE!!!!!! I know the answer I just need to know about the exponents...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{72x ^{3}y ^{16}}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you can convert square root of something to 1/2 exponents right \[\huge\rm \sqrt{x} =x^\frac{ 1 }{ 2 }\] what are the factors of 75 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1x^3 can be written as x^2 times x \[\huge\rm \sqrt{72 · x^2 · x· y^{16}} = \sqrt{72x} · x^\frac{ 2 }{ 2 } y^\frac{ 16 }{ 2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1let me know if you have question about that^^^^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why do you separate the x^2 and x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so i can take square root of x^2 we have to take out the variables from the square root or another way of taking square root of x^3 would dw:1441409742550:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and the Y too can you explain the Y why it goes outside

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1how many times does 2 goes into 3 ? one time right and remainder would be one dw:1441409878485:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1like i said we can convert root to exponent form \[\huge\rm \sqrt[n]{x^m} = x^\frac{ m }{ n }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.116 is divisible by 2 so i just convert square root to 1/2 exponent form dw:1441410065097:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if it can be divided it's automatically on the outside of the root?

phi
 one year ago
Best ResponseYou've already chosen the best response.1the easiest way to do these is as Nnesha showed. change square root to "exponent form" \[ \sqrt{y^{16} }= \left(y^{16}\right)^\frac{1}{2}\] now use the rule \( (a^b)^c= a^{bc} \) to write that as \(y^{16\cdot \frac{1}{2}}= y^8\) notice there is nothing strange (no square roots) it is just y^8

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yea here are some example \[\huge\rm \sqrt{a^8} = a^\frac{ 8 }{ 2 }=y^{4} \] \[\huge\rm \sqrt[3]{y^9} =y^\frac{ 9 }{ 3 }=y^{3}\] of the exponent of the variable not divisible by the root like for x^3 you can still write it as \[\huge\rm \sqrt{x^3} =x^\frac{ 3 }{ 2 }\] but the remainder is one so that's mean one x would remain under the root hope it makes sense

phi
 one year ago
Best ResponseYou've already chosen the best response.1the other way to think of it is \[ \sqrt{x \cdot x} = x\] if instead of x we had y^8 \[ \sqrt{y^8 \cdot y^8} = y^8\] that is the same pattern (and of course you know inside the square root y^8 * y^8 is y^16 so \[ \sqrt{y^{16}}=\sqrt{y^8 \cdot y^8} = y^8\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so i guess i was confused about the 16 cuz i thought it would be a y^4 because 4^2=16 but I think i got it now

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, it can get confusing . the 16 is an exponent. that is different from an ordinary number 16. if you get confused , remember y^16 is short for y*y*y*y..*y (y times itself 16 times) the square root of that is 1/2 of those y's or y*y*y*y*y*y*y*y (y times itself 8 times)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0got it now thanks phi!!
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