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mathmath333

  • one year ago

In how many ways can a selection can be made of at least one fruit out of 5 bananas,4 mangoes and 4 almonds ?

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can a selection can be made of at least}\hspace{.33em}\\~\\ & \normalsize \text{one fruit out of 5 bananas,4 mangoes and 4 almonds ? }\hspace{.33em}\\~\\ \end{align}}\)

  2. steve816
    • one year ago
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    5 * 4 * 4 = 80 ways

  3. mathmath333
    • one year ago
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    answer given is 149

  4. steve816
    • one year ago
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    What the hell? Let me think...

  5. ♪Chibiterasu
    • one year ago
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    Keep in mind that an almond is not a fruit.

  6. steve816
    • one year ago
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    LOL! Did they really have to trick us by putting almond xD

  7. amistre64
    • one year ago
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    since when is an almond not a fruit?

  8. amistre64
    • one year ago
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    mathmatikers are not botinists :)

  9. ♪Chibiterasu
    • one year ago
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    The almond is the seed of the almond fruit, the drupe.

  10. amistre64
    • one year ago
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    i smell a mole ...

  11. amistre64
    • one year ago
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    at least ... i cant make sense of the questions to be honest.

  12. mathmath333
    • one year ago
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    is the answer 13C1

  13. steve816
    • one year ago
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    it can't be 13C1

  14. anonymous
    • one year ago
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    13C1?

  15. phi
    • one year ago
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    I am thinking you can choose from 0 to 5 bananas so 6 choices 0 to 4 mangoes so 5 choices 0 to 4 almonds so 5 choices 6*5*5= 150 that includes the choice of 0 bananas, 0 mangoes , and 0 almonds so 149 with "fruits" if almonds are fruits

  16. phi
    • one year ago
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    if almonds are not fruits, this gives 150 - 5 (subtract off 0,0,0; 0,0,1; ...; 0,0,4) for 145

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