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Lena772

  • one year ago

A reaction has a rate law of : rate = k [ClO3-] [Cl-] [H+]2. If the initial reaction rate is 3.2E-3 M/s, then what is the rate constant if the initial concentrations are [ClO3-]o= 0.10 M, [Cl-]o= 0.10 M, [H+]o= 0.20 M ? (units are M-3 " s-1) A) 1.6 B) 8.0 C) 1.2 D) 0.62 E) none of these

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  1. Lena772
    • one year ago
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    @Abhisar

  2. Abhisar
    • one year ago
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    Ok, so have you tried it first urself?

  3. Lena772
    • one year ago
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    i think you would say 3.2 E-3 M/s = k [0.10] [0.10] [0.2] k= (3.2E-3/([0.10]*[0.1)]*[0.20])

  4. Abhisar
    • one year ago
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    Yes, that's correct c:

  5. Lena772
    • one year ago
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    k= 0.064

  6. Abhisar
    • one year ago
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    Check for one thung!!!

  7. Lena772
    • one year ago
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    so i guess D iis closest

  8. Abhisar
    • one year ago
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    No, you did a minor mistake !!!

  9. Lena772
    • one year ago
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    actually wrong brackets... 1.6

  10. Lena772
    • one year ago
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    A?

  11. Abhisar
    • one year ago
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    \(\sf Rate = k[ClO_3^-][Cl^-][H^+]^2\)

  12. Abhisar
    • one year ago
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    So, K should be equal to ???

  13. Lena772
    • one year ago
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    1.6*0.10*0.20*0.10=3.2 E-3 (the initial rate) so k is 1.6

  14. Lena772
    • one year ago
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    A :) thank you

  15. Lena772
    • one year ago
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    That was incorrect :(

  16. Abhisar
    • one year ago
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    Nuuuuu!!! \(\sf K=\Large \frac{Rate}{[ClO_3^-][Cl^-][H^+]^2}\)

  17. Abhisar
    • one year ago
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    You need to keep the order as given, I said you did a mistake. look above.. :(

  18. Lena772
    • one year ago
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    i got 1.6 when i calclulated that

  19. Abhisar
    • one year ago
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    It should be 8

  20. Abhisar
    • one year ago
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    \(\sf K=\Large \frac{3.2 \times 10^{-3}}{0.1\times 0.1 \times (0.2)^2}\)

  21. Lena772
    • one year ago
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    why is 0.2 squared

  22. Abhisar
    • one year ago
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    Because the Rate Law is given as \(\sf Rate = k[ClO_3^-][Cl^-][H^+]^2\)

  23. Lena772
    • one year ago
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    oh okay I didn't see that !

  24. Abhisar
    • one year ago
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    C;

  25. Lena772
    • one year ago
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    thank you!

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