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someone already told me this: ok... so for the 1st question let x be the smallest angle then the other 3 angles are x + 10, x + 20 and x + 30 and knowing the angles in a quadrilateral add to 360 you have an equation x + x + 10 + x + 20 + x + 30 = 360 so 4x + 60 = 360 just solve for x.
and my answer was 75 what do i do next??
It states that you have to add 10 for every new angle. If the original angle is 75, it would be 85, 95, and 105. Those angles added together equals 360.
and thats all i do for the 1st question?
thank you so much(: would you mind helping me on the last one?
I may be wrong, but I think the third polygon is also a pentagon. If the pentagon has equal angles then the vertically opposite angle would be 108, making it also a pentagon.
so its 2 different shapes?
Yeah, it's asking what the third regular polygon would be.
So the third regular polygon would be a pentagon
It's saying that the sides of the square and pentagon, AB and BC, are sides of a third regular polygon and it's asking you what that polygon would be.
oh okay i get it , thats it? nothing else? i just put pentagon?
Yep, that should do it
Well it asks how many sides it has so you should put 5 sides.
oh okay thanks again
Glad I could help :)