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anonymous

  • one year ago

Use a trigonometric ratio to find the value of x. Round the answer to the tenths’ place.

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  1. anonymous
    • one year ago
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  2. BloomLocke367
    • one year ago
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    Do you know about sin, cosin, and tangent and how to use them?

  3. anonymous
    • one year ago
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    Yes.

  4. BloomLocke367
    • one year ago
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    I was asking @barbdewysveck1 XD

  5. anonymous
    • one year ago
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    no

  6. anonymous
    • one year ago
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    Sorry..

  7. BloomLocke367
    • one year ago
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    don't be lol

  8. anonymous
    • one year ago
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    I figured it out! Thank you!!!!!

  9. BloomLocke367
    • one year ago
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    umm... didn't @barbdewysveck1 ask this question?

  10. anonymous
    • one year ago
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    whats the answer @KayKay83

  11. dinamix
    • one year ago
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    cos20 = 11/x @barbdewysveck1 i help u little

  12. BloomLocke367
    • one year ago
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    You shouldn't give or receive direct answers as they are against the CoC. @barbdewysveck1

  13. BloomLocke367
    • one year ago
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    but I'll happily walk you through what to do

  14. anonymous
    • one year ago
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    I got 2x^3 + x^2 + 4x - 3

  15. anonymous
    • one year ago
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    k just fast please

  16. anonymous
    • one year ago
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    \[2x^3+x^2+4x-3\]

  17. anonymous
    • one year ago
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    wrong question @BloomLocke367

  18. anonymous
    • one year ago
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    i mean @KayKay83

  19. anonymous
    • one year ago
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    srry @BloomLocke367

  20. BloomLocke367
    • one year ago
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    well you (should) know that \(\large sin=\frac{opposite}{hypotenuse},~cos=\frac{adjacent}{hypotenuse},~tan=\frac{opposite}{adjacent}\), right?

  21. BloomLocke367
    • one year ago
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    we are working on the problem you posted, right?

  22. anonymous
    • one year ago
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    yep

  23. BloomLocke367
    • one year ago
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    okay. Do you understand what I just posted?

  24. anonymous
    • one year ago
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    no

  25. anonymous
    • one year ago
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    No worries.

  26. BloomLocke367
    • one year ago
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    well, basically, that just tells you whether to use sine, cosine, or tangent to find the missing piece. You want to start from the angle, and opposite, hypotenuse, and adjacent all are referring to the placement of the angle you're looking at.

  27. BloomLocke367
    • one year ago
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    |dw:1441414606178:dw| That is the first triangle you have.

  28. BloomLocke367
    • one year ago
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    you want to be looking, first, at the angle they gave you, which is angle a. You already know the measurement now where is x in relation to a? is it the hypotenuse, is it adjacent to that angle, or is it opposite of that angle?

  29. BloomLocke367
    • one year ago
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    @barbdewysveck1

  30. anonymous
    • one year ago
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    is the hypot the 11 or he longer one

  31. BloomLocke367
    • one year ago
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    the hypotenuse is always the side that is across from the right angle. so it's the longest one.

  32. anonymous
    • one year ago
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    k

  33. BloomLocke367
    • one year ago
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    are you following me? or do I need to re-explain something?

  34. anonymous
    • one year ago
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    im followin

  35. anonymous
    • one year ago
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    Let f(x) = 2x^2+x-3 and g(x) = x-1. Perform the indicated operation, then find the domain. (f*g)(x)? is my answer correct? , 2x^3 + x^2 +4x -3: domain: positive real numbers? This was my question....so sorry for confusion!. Never mind. ;)

  36. BloomLocke367
    • one year ago
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    okay, so you know that side x is the hypotenuse.

  37. BloomLocke367
    • one year ago
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    the only other side you need to worry about is the one they gave you. is AC (11) adjacent to or opposite angle A?

  38. BloomLocke367
    • one year ago
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    @KayKay83, please do not post your question under somebody else's question. If you need help, open a question and you can tag me if you like and I'll help you to the best of my ability or you can find someone else to help.

  39. BloomLocke367
    • one year ago
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    @barbdewysveck1, are you still with me?

  40. anonymous
    • one year ago
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    yep

  41. BloomLocke367
    • one year ago
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    okay. is AC opposite or adjacent to angle A?

  42. anonymous
    • one year ago
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    adjacent

  43. anonymous
    • one year ago
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    I apologize. New to this and trying to learn rules.. So very sorry. 1st time I have ever asked a question. Never again.

  44. BloomLocke367
    • one year ago
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    yep :) now look at what I told you about sin, cos, and tan and tell me which one involves the hypotenuse and adjacent side.

  45. BloomLocke367
    • one year ago
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    It's alright, @KayKay83 :) Welcome to OpenStudy! I'll pm you a link to the CoC.

  46. BloomLocke367
    • one year ago
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    @barbdewysveck1

  47. BloomLocke367
    • one year ago
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    @barbdewysveck1, are you still here?

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