I have made a start, I am a little stuck in the middle:
w = 2 – 3i is a solution of the equation
\[ 3w^3-14 w^2+Aw– 26 = 0\]
where A is real. Find the value of A and the other two solutions of the equation
Stacey Warren - Expert brainly.com
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I know the solution has to be a conjugate pair, so I did
a bit stuck from here............plz help :)
OMGGGG I SOLVED IT!!!!!!!!!!!
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If anyone is interested in knowing..
I mirrored w^2-4w+13 to look like my original cubic by multiplying it with (kw+c)
then matched up the coefficients to the values i have and then found the values i didnt have (i.e A)
@LynFran thanks for the medal :D :D :D
you could also have done long division and set A so that the remainder is zero