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randomecorner

  • one year ago

what value of p solves the eqatian? p^-5=1/243

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  1. randomecorner
    • one year ago
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    i need help big time

  2. Nnesha
    • one year ago
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    this is like 5th time ii'm looking at this (exact same ) question

  3. Nnesha
    • one year ago
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    familiar with the exponent rule ? \[\huge\rm x^{-m} =\frac{ 1 }{ x^m}\]

  4. randomecorner
    • one year ago
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    nope

  5. randomecorner
    • one year ago
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    its 3 right?

  6. Nnesha
    • one year ago
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    x^{-m} is same as \[\huge\rm \frac{ x^{-m} }{ 1 }= \frac{ 1 }{ x^m }\] flip the fraction to convert negative to positive exponent

  7. randomecorner
    • one year ago
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    so it is 3

  8. Nnesha
    • one year ago
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    how did you get that ? plz explain

  9. randomecorner
    • one year ago
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    3*3*3*3*3=243

  10. Nnesha
    • one year ago
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    alright nice what about \[\huge\rm p^{-5}\]how would you get rid of the negative exponent ?

  11. randomecorner
    • one year ago
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    1/3

  12. Nnesha
    • one year ago
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    no just p^{-5}

  13. Nnesha
    • one year ago
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    remember flip the fraction and change the sign of exponent ?

  14. randomecorner
    • one year ago
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    wow thx

  15. randomecorner
    • one year ago
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    i feel dumb lol

  16. Nnesha
    • one year ago
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    well you're not

  17. randomecorner
    • one year ago
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    some of these math problems get fustrating

  18. randomecorner
    • one year ago
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    so the answer is 3 or 1/3?

  19. Nnesha
    • one year ago
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    well need to pay attention i'll give u an example \[\huge\rm a^{-2} = \frac{ 1 }{a^2 }\]

  20. Nnesha
    • one year ago
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    so \[\rm p^{-5}= ?\]

  21. randomecorner
    • one year ago
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    i was making sure because on the thing its a box to type the answer in

  22. randomecorner
    • one year ago
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    p^-5=3

  23. Nnesha
    • one year ago
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    or you can substitute p for 1/3 and then for 3 to check ur answer you should get equal sides at the end

  24. Nnesha
    • one year ago
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    how would you convert p^{-5} to positive exponent ?

  25. randomecorner
    • one year ago
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    flip the eqation

  26. Nnesha
    • one year ago
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    yes right how would you do that p^{-5}/1 = ?

  27. randomecorner
    • one year ago
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    -5\p=1\3

  28. randomecorner
    • one year ago
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    //

  29. randomecorner
    • one year ago
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    s in the box it is 1/3? or 3 k12 is usally not settled about that

  30. Nnesha
    • one year ago
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    how did you get 1/3

  31. Nnesha
    • one year ago
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    3* 3*3*3*3 = 243 right agree ?

  32. randomecorner
    • one year ago
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    imso confussed again sorry

  33. randomecorner
    • one year ago
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    and also 1/3 goes into 1/243 5 times

  34. Nnesha
    • one year ago
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    when you multiply same bases we should add their exponents so \[\huge\rm 3^1 \times 3^1 \times 3^1 \times 3^1 \times 3^1 =3^{1+1+1+1+1}\]

  35. randomecorner
    • one year ago
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    yes

  36. Nnesha
    • one year ago
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    so \[\huge\rm p^{-5} = \frac{ 1 }{ 3^5 }\] now move 3^5 at the numerator flip the fraction when you do that sign of the `exponent` would change

  37. Nnesha
    • one year ago
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    or in other words what is the reciprocal of 1/3^5 ??

  38. randomecorner
    • one year ago
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    1/15?

  39. Nnesha
    • one year ago
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    it's \[\huge\rm \frac{ 1 }{ 3^5 }\] 3 to the 5th power not 3 times 5

  40. randomecorner
    • one year ago
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    sorry that's what i should of wrote insted

  41. Nnesha
    • one year ago
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    okay so when you flip 1/3^5 what would you get ?

  42. randomecorner
    • one year ago
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    1/243

  43. randomecorner
    • one year ago
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    the answer is 3

  44. Nnesha
    • one year ago
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    well we changed 243 to 3^5 you should remember these exponents rule \[\huge\rm x^{-m} =\frac{ 1 }{ x^m } ~~and~~ \frac{ 1}{ 2^{-m} }= 2^m\] you have to flip the fraction to change negative to postiive exponent

  45. Nnesha
    • one year ago
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    i've few mints have to go

  46. Nnesha
    • one year ago
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    well yes \[3^{-5} = \frac{ 1 }{ 3^5 }\]

  47. Nnesha
    • one year ago
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    which is equal to right side

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