randomecorner
  • randomecorner
what value of p solves the eqatian? p^-5=1/243
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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randomecorner
  • randomecorner
i need help big time
Nnesha
  • Nnesha
this is like 5th time ii'm looking at this (exact same ) question
Nnesha
  • Nnesha
familiar with the exponent rule ? \[\huge\rm x^{-m} =\frac{ 1 }{ x^m}\]

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randomecorner
  • randomecorner
nope
randomecorner
  • randomecorner
its 3 right?
Nnesha
  • Nnesha
x^{-m} is same as \[\huge\rm \frac{ x^{-m} }{ 1 }= \frac{ 1 }{ x^m }\] flip the fraction to convert negative to positive exponent
randomecorner
  • randomecorner
so it is 3
Nnesha
  • Nnesha
how did you get that ? plz explain
randomecorner
  • randomecorner
3*3*3*3*3=243
Nnesha
  • Nnesha
alright nice what about \[\huge\rm p^{-5}\]how would you get rid of the negative exponent ?
randomecorner
  • randomecorner
1/3
Nnesha
  • Nnesha
no just p^{-5}
Nnesha
  • Nnesha
remember flip the fraction and change the sign of exponent ?
randomecorner
  • randomecorner
wow thx
randomecorner
  • randomecorner
i feel dumb lol
Nnesha
  • Nnesha
well you're not
randomecorner
  • randomecorner
some of these math problems get fustrating
randomecorner
  • randomecorner
so the answer is 3 or 1/3?
Nnesha
  • Nnesha
well need to pay attention i'll give u an example \[\huge\rm a^{-2} = \frac{ 1 }{a^2 }\]
Nnesha
  • Nnesha
so \[\rm p^{-5}= ?\]
randomecorner
  • randomecorner
i was making sure because on the thing its a box to type the answer in
randomecorner
  • randomecorner
p^-5=3
Nnesha
  • Nnesha
or you can substitute p for 1/3 and then for 3 to check ur answer you should get equal sides at the end
Nnesha
  • Nnesha
how would you convert p^{-5} to positive exponent ?
randomecorner
  • randomecorner
flip the eqation
Nnesha
  • Nnesha
yes right how would you do that p^{-5}/1 = ?
randomecorner
  • randomecorner
-5\p=1\3
randomecorner
  • randomecorner
//
randomecorner
  • randomecorner
s in the box it is 1/3? or 3 k12 is usally not settled about that
Nnesha
  • Nnesha
how did you get 1/3
Nnesha
  • Nnesha
3* 3*3*3*3 = 243 right agree ?
randomecorner
  • randomecorner
imso confussed again sorry
randomecorner
  • randomecorner
and also 1/3 goes into 1/243 5 times
Nnesha
  • Nnesha
when you multiply same bases we should add their exponents so \[\huge\rm 3^1 \times 3^1 \times 3^1 \times 3^1 \times 3^1 =3^{1+1+1+1+1}\]
randomecorner
  • randomecorner
yes
Nnesha
  • Nnesha
so \[\huge\rm p^{-5} = \frac{ 1 }{ 3^5 }\] now move 3^5 at the numerator flip the fraction when you do that sign of the `exponent` would change
Nnesha
  • Nnesha
or in other words what is the reciprocal of 1/3^5 ??
randomecorner
  • randomecorner
1/15?
Nnesha
  • Nnesha
it's \[\huge\rm \frac{ 1 }{ 3^5 }\] 3 to the 5th power not 3 times 5
randomecorner
  • randomecorner
sorry that's what i should of wrote insted
Nnesha
  • Nnesha
okay so when you flip 1/3^5 what would you get ?
randomecorner
  • randomecorner
1/243
randomecorner
  • randomecorner
the answer is 3
Nnesha
  • Nnesha
well we changed 243 to 3^5 you should remember these exponents rule \[\huge\rm x^{-m} =\frac{ 1 }{ x^m } ~~and~~ \frac{ 1}{ 2^{-m} }= 2^m\] you have to flip the fraction to change negative to postiive exponent
Nnesha
  • Nnesha
i've few mints have to go
Nnesha
  • Nnesha
well yes \[3^{-5} = \frac{ 1 }{ 3^5 }\]
Nnesha
  • Nnesha
which is equal to right side

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