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anonymous
 one year ago
Choose any four (4) of the five radical equations below. Solve each equation, showing all steps
leading to your answer. Then check your answer to determine if any of the solutions are
extraneous
1. √5x  x = 0
2. √(2x + 1) + 1 = x
3. √(3x  2) + 3 = 4x
can someone please help me solve it ?
anonymous
 one year ago
Choose any four (4) of the five radical equations below. Solve each equation, showing all steps leading to your answer. Then check your answer to determine if any of the solutions are extraneous 1. √5x  x = 0 2. √(2x + 1) + 1 = x 3. √(3x  2) + 3 = 4x can someone please help me solve it ?

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.0steps isolate the radicand to one side of the equation. remember whatever you do to one side also do to the other square each side to get rid of the radicand and maintain the balance isolate the terms with the variable to one side simplify if possible divide by the coefficient of the variable take a minute to review then I'll walk you through one after which you can try the others on your own and I will verify if you show your work and ask me to

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441428621396:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0problem 3 the radicand is labeled to isolate by subtracting 3 square each side and simplify. this gives a quadratic we can solve by factoring/completing the square/ graphing/matrices or using the formula. minor note to the steps I wrote if it was a linear equation divide by the coefficient of the variable if like in this case you have a quadratic solve using one of the 5 methods

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to solve quadratic equations?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0yes one of the methods

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait , i am bit lost . when u square (4x  3)^2 , isn't the answer 16x^2  12x + 9 ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0good catch thanks dw:1441430085255:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441430227757:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now we factor it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do we factor it ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I am going to use the formula

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441430939433:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441430974635:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0reply with above and identify your a, b, c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so a = 16 , b = 27 , c = 11 right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then using the above formula we will have : dw:1441431330504:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441431722636:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441431470048:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441431767526:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is my answer correct ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441431858754:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0it can't be because you have the wrong C

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441432220054:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isn't 2 + 9 = 11 ? since 3x  2 = 16x^2  24x + 9 16x^2  24x  3x + 9 + 2 = 16x^2  27x + 11 ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0think we have another error the graph shows 2.027

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0think I am too tired to be on here but happy you grasp something sorry need to be off right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so i think i am understanding the question number 3. thank you so much for ur help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was hoping u would help in question number 1 or 2 ? but if ur busy then its ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For question 1: rewrite your function: \(\sqrt{5}xx=0\) \[(\sqrt{5}1)x=0\]\[\boxed{x= \frac{0}{\sqrt{5}1} = 0}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it \(\sqrt{5}x\) or \(\sqrt{5x}\)?
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